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## Latest Messages

Feb 20
So that, the first twin isolated square-free numbers are ${17,19}$, sorry.

Feb 17
This works even when the base is a Gaussian integer: Reading GPRC: gprc.txt ...Done. GP/PARI CALCULATOR Version 2.6.1 (alpha) i686 running mingw (ix86/GMP-5.0.1 kernel) 32-bit version compiled: Sep 20 2013, gcc version 4.6.3 (GCC) (readline v6.2 enabled, extended help enabled) Copyright (C) 2000-2013 The PARI Group PARI/GP is free software, covered by the GNU General Public License, and comes WITHOUT ANY WARRANTY WHATSOEVER. Type ? for help, \q to quit. Type ?12 for how to get moral (and possibly technical) support. parisize = 4000000, primelimit = 500000 (17:50) gp > ((14+15*I)^104-1)/105 = -249662525598174865517621222098021785366399633335910441957688800663877876192221716937263714468906280908614454012799368615180549371243472 - 118511838209654103558982122027130965758920275429164915998560474682902951765213030198935065103035392002339412087987613469408163154998032*I (17:51) gp >

Feb 17
This works even when the base is a Gaussian integer: Reading GPRC: gprc.txt ...Done. GP/PARI CALCULATOR Version 2.6.1 (alpha) i686 running mingw (ix86/GMP-5.0.1 kernel) 32-bit version compiled: Sep 20 2013, gcc version 4.6.3 (GCC) (readline v6.2 enabled, extended help enabled) Copyright (C) 2000-2013 The PARI Group PARI/GP is free software, covered by the GNU General Public License, and comes WITHOUT ANY WARRANTY WHATSOEVER. Type ? for help, \q to quit. Type ?12 for how to get moral (and possibly technical) support. parisize = 4000000, primelimit = 500000 (17:50) gp > ((14+15*I)^104-1)/105 %1 = -249662525598174865517621222098021785366399633335910441957688800663877876192221716937263714468906280908614454012799368615180549371243472 - 118511838209654103558982122027130965758920275429164915998560474682902951765213030198935065103035392002339412087987613469408163154998032*I (17:51) gp >

Jan 27
Fermat's theorem works even if the base is a Gausssian integer subject to a) the prime under consideration is of shape 4m+1 and b) the exponent and base are co-prime. ((2+3*I)^16-1)/17 = -47977440 - 803040*I

Jan 27
Fermat's theorem works even if the base is a Gausssian integer subject to a) the prime under consideration is of shape 4m+1 and b) the exponent and base are co-prime. ((2+3*I)^16-1)/17 %1 = -47977440 - 803040*I

Jan 27
Fermat's theorem works even if the base is a Gausssian integer subject to a) the prime under consideration is of shape 4m+1 and b) the exponent and base are co-prime. ((2+3*I)^16-1)/17 %1 = -47977440 - 803040*I

Jan 26
Join maths corner on facebook. Procedure: join fb and I can add you as member - your contributions are welcome.

[p] Happy by akdevaraj Jan 26
Happy to see Pahio is again active on this site!

[p] Happy by akdevaraj Jan 26
Happy to see Pahio is again active on this site!

[p] Happy by akdevaraj Jan 26
Happy to see Pahio is again active on this site!

[p] Happy by akdevaraj Jan 26
Happy to see Pahio is again active on this site!

Jan 5
1 11 111 1111... This could be an example to here, the normal.

Jan 1
I'm think k0 come from the cutoff frequency designing , the media . Hence, k0 from (b) process !.

[p] real name? by WM 16-10-29
You are right. I have included your statement into https://www.hs-augsburg.de/~mueckenh/Transfinity/Transfinity/pdf Would you disclose your real name? Regards, WM