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Corrections for $\operatorname{ker} L=\{0\}$ if and only if $L$ is injective
1. proof supplied by Wkbj79 on 2006-10-27 11:38:28 (accepted)
2. two addenda by alozano on 2006-10-26 09:03:47 (accepted)
3. remove theorem numbering by alozano on 2006-10-26 09:01:12 (accepted)
4. suppress link by Mathprof on 2006-08-02 10:52:03 (accepted)
5. typo by yark on 2006-07-25 16:20:21 (accepted)
6. typos by yark on 2004-10-17 11:40:11 (accepted)

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