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<record version="7" id="10026">
 <title>quadratic equation in $\mathbb{C}$</title>
 <name>QuadraticEquationInMathbbC</name>
 <created>2007-11-01 17:53:46</created>
 <modified>2007-11-05 06:55:22</modified>
 <type>Theorem</type>
<parent id="7175">taking square root algebraically</parent>
 <creator id="2872" name="pahio"/>
 <author id="2872" name="pahio"/>
 <classification>
	<category scheme="msc" code="12D99"/>
	<category scheme="msc" code="30-00"/>
 </classification>
 <synonyms>
	<synonym concept="quadratic equation in $\mathbb{C}$" alias="quadratic equation"/>
 </synonyms>
 <related>
	<object name="QuadraticFormula"/>
	<object name="DerivationOfQuadraticFormula"/>
	<object name="CardanosDerivationOfTheCubicFormula"/>
 </related>
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 <content>The quadratic formula
$$x = \frac{-b\pm\sqrt{b^2-4ac}}{2a}$$
for solving the quadratic equation
\begin{align}
ax^2+bx+c = 0
\end{align}
with real coefficients $a$, $b$, $c$ is valid as well for all complex values of these coefficients ($a \neq 0$), when the square root is determined as is presented in the \PMlinkname{parent entry}{TakingSquareRootAlgebraically}.\\

{\em Proof.}  Multiplying (1) by $4a$ and adding $b^2$ to both sides gives an \PMlinkname{equivalent}{Equivalent3} equation
$$4a^2x^2+4abx+4ac+b^2 = b^2$$
or
$$(2ax)^2+2\cdot2ax\cdot{b}+b^2 = b^2-4ac$$
or furthermore
$$(2ax+b)^2 = b^2-4ac.$$
Taking square root algebraically yields
$$2ax+b = \pm\sqrt{b^2-4ac},$$
which implies the quadratic formula.\\


\textbf{Note.}  A \PMlinkescapetext{similar} quadratic formula is meaningful besides $\mathbb{C}$ also in other fields with characteristic $\neq 2$\, if one can find the needed ``square root'' (this may require a field extension).


</content>
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