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<record version="1" id="10042">
 <title>polarization identity</title>
 <name>PolarizationIdentity3</name>
 <created>2007-11-15 17:55:45</created>
 <modified>2007-11-15 17:55:45</modified>
 <type>Theorem</type>
 <creator id="17536" name="asteroid"/>
 <author id="17536" name="asteroid"/>
 <classification>
	<category scheme="msc" code="46C05"/>
 </classification>
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 <content>{\bf Theorem} [polarization identity] {\bf -} Let $X$ be an inner product space over $\mathbb{R}$. The following identity holds for every $x, y \in X$:
\begin{displaymath}
\langle x, y \rangle = \frac{1}{4}(\|x +y \|^2 - \|x-y\|^2)
\end{displaymath}

If $X$ is an inner product space over $\mathbb{C}$ instead, the identity becomes
\begin{displaymath}
\langle x, y \rangle = \frac{1}{4}(\|x +y \|^2 - \|x-y\|^2) + \frac{1}{4}i(\|x+iy\|^2-\|x-iy\|^2)
\end{displaymath}

{\bf Remark -} This result shows that the inner product of $X$ is determined by the norm. Moreover, it can be shown that if a normed space $V$ \PMlinkescapetext{satisfies} the parallelogram law, the above formulas define an inner product compatible with the norm of $V$.</content>
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