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 <title>properties of states</title>
 <name>PropertiesOfStates</name>
 <created>2008-01-23 17:57:56</created>
 <modified>2008-01-23 18:01:26</modified>
 <type>Theorem</type>
<parent id="4574">state</parent>
 <creator id="17536" name="asteroid"/>
 <author id="17536" name="asteroid"/>
 <classification>
	<category scheme="msc" code="46L05"/>
	<category scheme="msc" code="46L30"/>
 </classification>
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 <content>Let $\mathcal{A}$ be a \PMlinkname{$C^*$-algebra}{CAlgebra} and $x \in \mathcal{A}$. 

Let $S(\mathcal{A})$ and $P(\mathcal{A})$ denote the \PMlinkname{state}{State} space and the pure state space of $\mathcal{A}$, respectively.

\subsection{States}
The \PMlinkescapetext{state} space is sufficiently large to reveal many \PMlinkescapetext{properties} of elements of a $C^*$-algebra.

{\bf Theorem 1-} We have that
\begin{itemize}
\item $S(\mathcal{A})$ separates points, i.e. $x= 0$ if and only if $\phi(x) = 0$ for all $\phi \in S(\mathcal{A})$.
\item $x$ is \PMlinkname{self-adjoint}{InvolutaryRing} if and only if $\phi(x) \in \mathbb{R}$ for all $\phi \in S(\mathcal{A})$.
\item $x$ is positive if and only if $\phi(x) \geq 0$ for all $\phi \in S(\mathcal{A})$.
\item If $x$ is \PMlinkname{normal}{InvolutaryRing}, then $\phi(x) = \|x\|$ for some $\phi \in S(\mathcal{A})$.
\end{itemize}

\subsection{Pure states}

The pure state space is also sufficiently large to \PMlinkescapetext{satisfy} the \PMlinkescapetext{properties} of Theorem 1. Hence, we can replace $S(\mathcal{A})$ by $P(\mathcal{A})$, or by any other family of linear functionals $F$ such that $P(\mathcal{A}) \subset F \subset S(\mathcal{A})$, in the previous result.

{\bf Theorem 2 -} We have that
\begin{itemize}
\item $P(\mathcal{A})$ separates points, i.e. $x= 0$ if and only if $\phi(x) = 0$ for all $\phi \in P(\mathcal{A})$.
\item $x$ is \PMlinkescapetext{self-adjoint} if and only if $\phi(x) \in \mathbb{R}$ for all $\phi \in P(\mathcal{A})$.
\item $x$ is positive if and only if $\phi(x) \geq 0$ for all $\phi \in P(\mathcal{A})$.
\item If $x$ is \PMlinkescapetext{normal}, then $\phi(x) = \|x\|$ for some $\phi \in P(\mathcal{A})$.
\end{itemize}

{\bf \PMlinkescapetext{Proposition} -} Every multiplicative linear functional on $\mathcal{A}$ is a pure state.</content>
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