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<record version="9" id="10760">
 <title>commensurable numbers</title>
 <name>CommensurableNumbers</name>
 <created>2008-07-08 16:01:55</created>
 <modified>2009-08-24 15:11:01</modified>
 <type>Definition</type>
<parent id="454">real number</parent>
 <creator id="2872" name="pahio"/>
 <author id="2872" name="pahio"/>
 <classification>
	<category scheme="msc" code="03E02"/>
	<category scheme="msc" code="12D99"/>
 </classification>
 <defines>
	<concept>commensurable</concept>
	<concept>incommensurable</concept>
	<concept>commensurability</concept>
 </defines>
 <related>
	<object name="RationalAndIrrational"/>
	<object name="CommensurableSubgroups"/>
 </related>
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 <content>Two positive real numbers $a$ and $b$ are {\em commensurable}, iff there exists a positive real number $u$ such that
\begin{align}
a = mu, \quad b = nu
\end{align}
with some positive integers $m$ and $n$.

If the positive numbers $a$ and $b$ are not commensurable, they are {\em incommensurable}.\\

\textbf{Theorem.}\, The positive numbers $a$ and $b$ are commensurable if and only if their ratio is a rational number 
$\displaystyle\frac{m}{n}$\, ($m,\,n \in \mathbb{Z}$).\\

{\em Proof.}\, The equations (1) imply the \PMlinkname{proportion}{ProportionEquation}
\begin{align}
\frac{a}{b} = \frac{m}{n}.
\end{align}
Conversely, if (2) is valid with\, $m,\,n \in \mathbb{Z}$,\, then we can write
$$a = m\!\cdot\!\frac{b}{n}, \quad b = n\!\cdot\!\frac{b}{n},$$
which means that $a$ and $b$ are multiples of $\displaystyle\frac{b}{n}$ and thus commensurable.\, Q.E.D.\\

\textbf{Example.}\, The lengths of the side and the diagonal of \PMlinkid{square}{1086} are always incommensurable.

\subsection{Commensurability as relation}

\begin{itemize}

\item The commensurability is an equivalence relation in the set $\mathbb{R}_+$ of the positive reals:\, the reflexivity and the symmetry are trivial;\, if\, $a\!:\!b = r$\, and\, $b\!:\!c = s$,\, then\, $a\!:\!c = (a\!:\!b)(b\!:\!c) = rs$,\, whence one obtains the transitivity.\\

\item The equivalence classes of the commensurability are of the form
$$[\varrho] \,:=\, \{r\varrho\,\vdots\;\; r \in \mathbb{Q}_+\}.$$

\item One of the equivalence classes is the set\, $[1] = \mathbb{Q}_+$\, of the positive rationals, all others consist of positive irrational numbers.

\item If one sets\; $[\varrho]\!\cdot\![\sigma] := [\varrho\sigma]$,\, the equivalence classes form with respect to this binary operation an Abelian group.

\end{itemize}</content>
</record>
