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<record version="4" id="11312">
 <title>left and right cosets in a double coset</title>
 <name>LeftAndRightCosetsInADoubleCoset</name>
 <created>2008-12-06 16:15:37</created>
 <modified>2008-12-06 19:02:11</modified>
 <type>Theorem</type>
<parent id="8408">double coset</parent>
 <creator id="17536" name="asteroid"/>
 <author id="17536" name="asteroid"/>
 <classification>
	<category scheme="msc" code="20A05"/>
 </classification>
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 <content>\PMlinkescapeword{right}

Let $H$ and $K$ be subgroups of a group $G$. Every double coset $HgK$, with $g \in G$, is a union of \PMlinkname{right}{Coset} or left cosets, since
\begin{align*}
HgK = \bigcup_{k \in K} Hgk\; = \bigcup_{h \in H} hgK,
\end{align*}
but these unions need not be disjoint. In particular, from the above equality we cannot say how many right (or left) cosets fit in a double coset.

The following proposition aims to clarify this.

$\,$

{\bf \PMlinkescapetext{Proposition} -} Let $H$ and $K$ be subgroups of a group $G$ and $g \in G$. We have that
\begin{align*}
HgK = \bigcup_{[k]\, \in\, (K \cap g^{-1}Hg) \backslash K} Hgk\; = \bigcup_{[h]\, \in\, H / (H \cap gKg^{-1})} hgK
\end{align*}
hold as disjoint unions. In particular, the number of right and left cosets in $HgK$ is respectively given by
\begin{align*}
\#(H \backslash HgK) = [K: K \cap g^{-1}Hg]\\
\#(HgK/K) =[H: H \cap gKg^{-1}]
\end{align*}

\subsection{Remarks}

\begin{itemize}
\item The number of right and left cosets in a double coset does not coincide in general, not \PMlinkescapetext{even} for double cosets of the form $HgH$.
\end{itemize}

\begin{thebibliography}{9}
\bibitem{krieg} A. Krieg, \emph{\PMlinkescapetext{Hecke algebras}}, Mem. Amer. Math. Soc., no. 435, vol. 87, 1990.
\end{thebibliography}</content>
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