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<record version="2" id="11437">
 <title>Stone-Weierstrass theorem for locally compact spaces</title>
 <name>StoneWeierstrassTheoremForLocallyCompactSpaces</name>
 <created>2009-01-01 21:54:29</created>
 <modified>2009-01-02 14:24:57</modified>
 <type>Definition</type>
<parent id="2984">Stone-Weierstrass theorem</parent>
 <creator id="17536" name="asteroid"/>
 <author id="17536" name="asteroid"/>
 <classification>
	<category scheme="msc" code="46J10"/>
 </classification>
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 <content>The following results generalize the Stone-Weierstrass theorem (and its \PMlinkname{complex version}{StoneWeierstrassTheoremComplexVersion}) for locally compact spaces. The cost of this generalization is that one no longer deals with all continuous functions, but only those that vanish at infinity.

\subsection*{Real version}

{\bf Theorem -} Let $ X$ be a locally compact space and $C_0(X, \mathbb{R})$ the algebra of continuous functions $X \to \mathbb{R}$ that \PMlinkname{vanish at infinity}{ VanishAtInfinity}, endowed with the sup norm $\Vert \cdot \Vert _{\infty}$. Let $\mathcal{A}$ be a subalgebra of $C_0(X; \mathbb{R})$ for which the following conditions hold:

\begin{enumerate}
\item $\forall x, y \in X, x \ne y, \exists f \in \mathcal{A} : f(x) \neq f(y)\;$, i.e. $ \mathcal{A}$ separates points.
\item For each $x \in X$ there exists $f \in \mathcal{A}$ such that $f(x) \neq 0$.
\end{enumerate}

Then $\mathcal{A}$ is dense in $C_0(X; \mathbb{R})$.

\subsection*{Complex version}

{\bf Theorem -} Let $X$ be a locally compact space and $C_0(X)$ the algebra of continuous functions $X \to \mathbb{C}$ that vanish at infinity, endowed with the sup norm $\Vert \cdot \Vert _{\infty}$. Let $\mathcal{A}$ be a subalgebra of $C_0(X)$ for which the following conditions hold:

\begin{enumerate}
\item $\forall x, y \in X, x \ne y, \exists f \in \mathcal{A} : f(x) \neq f(y)\;$, i.e. $\mathcal{A}$ separates points.
\item For each $x \in X$ there exists $f \in \mathcal{A}$ such that $f(x) \neq 0$.
\item If $f \in \mathcal{A}$ then $\overline{f} \in \mathcal{A}\;$, i.e. $ \mathcal{A}$ is a self-adjoint subalgebra of $ C(X)$.
\end{enumerate}

Then $\mathcal{A}$ is dense in $C_0(X)$.
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