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 <title>base and height of triangle</title>
 <name>BaseAndHeightOfTriangle</name>
 <created>2009-02-21 08:16:27</created>
 <modified>2009-02-25 18:49:40</modified>
 <type>Definition</type>
<parent id="139">triangle</parent>
 <creator id="2872" name="pahio"/>
 <author id="2872" name="pahio"/>
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	<category scheme="msc" code="51M04"/>
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 <defines>
	<concept>base</concept>
	<concept>height</concept>
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	<synonym concept="base and height of triangle" alias="base of triangle"/>
	<synonym concept="base and height of triangle" alias="height of triangle"/>
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	<object name="AreaOfAPolygonalRegion"/>
	<object name="HeightOfATriangle"/>
	<object name="Area2"/>
	<object name="ProjectionFormula"/>
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 <keywords>
	<term>triangle</term>
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Considering the area of a triangle, one usually names a side of the triangle to be its \emph{base}.\, For expressing the calculation way of the area of the triangle, one then uses the \emph{height}, which means the perpendicular distance of the vertex, \PMlinkescapetext{opposite} to the base side, from the line determined by the base.\, In the above two triangles, the heights $h_1$ and $h_2$ correspond the horizontal \PMlinkescapetext{bases}.

The rule for the calculation reads
$$\mbox{area \;=\; base times height divided by 2}$$\\



In the below figure, there is the illustration of the rule.\, The parallelogram $ABCD$ has been divided by the diagonal $BD$ into two triangles, which are congruent by the ASA criterion (see the alternate interior angles).\, Thus the both triangles have the areas half of the area of the parallelogram, which in turn has the common base $AB$ and the common height $h$ with the triangle $ABD$.
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\textbf{Note.}\, In an isosceles triangle, one sometimes calls the two equal sides the \emph{legs} and the third side the \emph{base}.
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