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 <title>fundamental theorem of integral calculus</title>
 <name>FundamentalTheoremOfIntegralCalculus</name>
 <created>2009-02-25 10:29:40</created>
 <modified>2009-12-01 19:43:16</modified>
 <type>Theorem</type>
<parent id="1990">mean-value theorem</parent>
 <creator id="2872" name="pahio"/>
 <author id="2872" name="pahio"/>
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	<category scheme="msc" code="26A06"/>
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 <content>The derivative of a real function, which has on a whole interval a \PMlinkname{constant}{ConstantFunction} value $c$, vanishes in every point of this interval:
$$\frac{d}{dx}c \;=\; 0$$\\

The converse theorem of this is also true.\, Ernst Lindel\"of calls it the \emph{fundamental theorem of integral calculus} (in Finnish \emph{integraalilaskun peruslause}).\, It can be formulated as

\textbf{Theorem.}\, If a real function in continuous and its derivative vanishes in all points of an interval, the value of this function does not change on this interval.

\emph{Proof.}\, We make the antithesis that there were on the interval two distinct points $x_1$ and $x_2$ with\, $f(x_1) \neq f(x_2)$.\, Then the mean-value theorem guarantees a point $\xi$ between $x_1$ and $x_2$ such that
$$f'(\xi) \;=\; \frac{f(x_1)\!-\!f(x_2)}{x_1\!-\!x_2},$$
which value is distinct from zero.\, This is, however, impossible by the assumption of the theorem.\, So the antithesis is wrong and the theorem \PMlinkescapetext{right}.\\

The contents of the theorem may be expressed also such that if two functions have the same derivative on a whole interval, then the difference of the functions is constant on this interval.\, Accordingly, if $F$ is an antiderivative of a function $f$, then any other antiderivative of $f$ has the form $x \mapsto F(x)\!+\!C$, where $C$ is a constant.





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