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<record version="1" id="11743">
 <title>local homeomorphism</title>
 <name>LocalHomeomorphism</name>
 <created>2009-04-18 11:40:09</created>
 <modified>2009-04-18 11:40:09</modified>
 <type>Definition</type>
<parent id="912">homeomorphism</parent>
 <creator id="16130" name="joking"/>
 <author id="16130" name="joking"/>
 <classification>
	<category scheme="msc" code="54C05"/>
 </classification>
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 <content>\textbf{Definition.} Let $X$ and $Y$ be topological spaces. Continuous map $f:X\to Y$ is said to be \textit{locally invertible in $x\in X$} iff there exist open subsets $U\subseteq X$ and $V\subseteq Y$ such that $x\in U$, $f(x)\in V$ and the restriction $$f:U\to V$$ is a homeomorphism. If $f$ is locally invertible in every point of $X$, then $f$ is called a \textit{local homeomorphism}.

\textbf{Examples.} Of course every homeomorphism is a local homeomorphism, but the converse is not true. For example, let $f:\mathbb{C}\to\mathbb{C}$ be an exponential function, i.e. $f(z)=e^z$. Then $f$ is a local homeomorphism, but it is not a homeorphism (indeed, $f(z)=f(z+2\pi i)$ for any $z\in\mathbb{C}$).

One of the most important theorem of differential calculus (i.e. inverse function theorem) states, that if $f:M\to N$ is a $C^1$-map between $C^1$-manifolds such that $T_{x}f:T_{x}M\to T_{f(x)}N$ is a linear isomorphism for a given $x\in M$, then $f$ is locally invertible in $x$ (in this case the local inverse is even a $C^1$-map).</content>
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