<?xml version="1.0" encoding="UTF-8"?>

<record version="5" id="1334">
 <title>second isomorphism theorem</title>
 <name>SecondIsomorphismTheorem</name>
 <created>2002-01-05 04:06:09</created>
 <modified>2007-07-04 05:42:00</modified>
 <type>Theorem</type>
 <creator id="24" name="djao"/>
 <author id="24" name="djao"/>
 <classification>
	<category scheme="msc" code="20A05"/>
	<category scheme="msc" code="13C99"/>
 </classification>
 <preamble>\usepackage{amssymb}
\usepackage{amsmath}
\usepackage{amsfonts}
\usepackage{graphicx}
\usepackage{xypic}</preamble>
 <content>Let $(G,*)$ be a group. Let $H$ be a subgroup of $G$ and let $K$ be a normal subgroup of $G$. Then
\begin{itemize}
\item $HK := \{ h*k \mid h \in H,\ k \in K \}$ is a subgroup of $G$,
\item $K$ is a normal subgroup of $HK$,
\item $H \cap K$ is a normal subgroup of $H$,
\item There is a natural group isomorphism $H/(H \cap K) = HK/K$.
\end{itemize}

The same statement also holds in the category of modules over a fixed ring (where normality is neither needed nor relevant), and indeed can be formulated so as to hold in any abelian category.</content>
</record>
