<?xml version="1.0" encoding="UTF-8"?>

<record version="10" id="142">
 <title>median</title>
 <name>Median</name>
 <created>2001-10-06 17:32:20</created>
 <modified>2007-10-08 23:45:27</modified>
 <type>Definition</type>
 <creator id="3771" name="CWoo"/>
 <author id="3771" name="CWoo"/>
 <author id="6075" name="rspuzio"/>
 <author id="3" name="drini"/>
 <classification>
	<category scheme="msc" code="51-00"/>
 </classification>
 <related>
	<object name="Triangle"/>
	<object name="ApolloniusTheorem"/>
	<object name="Orthocenter"/>
	<object name="CevasTheorem"/>
	<object name="Centroid"/>
	<object name="ProofOfApolloniusTheorem2"/>
	<object name="ParallelogramLaw"/>
	<object name="TrigonometricVersionOfCevasTheorem"/>
	<object name="ProofOfParallelogramLaw"/>
	<object name="HeightOfATriangle"/>
	<object name="Cevian"/>
 </related>
 <keywords>
	<term>Triangle</term>
	<term>Geometry</term>
 </keywords>
 <preamble>\usepackage{amssymb}
\usepackage{amsmath}
\usepackage{amsfonts}
\usepackage{graphicx}
\usepackage{xypic}</preamble>
 <content>The \emph{median} of a triangle is a line segment joining a vertex with the midpoint of the opposite side.

In the next figure, $AA'$ is a median. That is, $BA'=A'C$, or equivalently, $A'$ is the midpoint of $BC$.

\begin{center}
\includegraphics[scale=0.5]{median}
\end{center}

If the length of the three sides of the triangle are known, the length of the medians can be found by means of Apollonius theorem.</content>
</record>
