<?xml version="1.0" encoding="UTF-8"?>

<record version="8" id="1530">
 <title>Urysohn's lemma</title>
 <name>UrysohnsLemma</name>
 <created>2002-01-22 12:30:30</created>
 <modified>2007-05-23 13:12:02</modified>
 <type>Theorem</type>
 <creator id="2760" name="yark"/>
 <author id="2760" name="yark"/>
 <author id="27" name="Evandar"/>
 <classification>
	<category scheme="msc" code="54D15"/>
 </classification>
 <defines>
	<concept>Urysohn function</concept>
	<concept>normal space</concept>
	<concept>normal topological space</concept>
	<concept>normal</concept>
	<concept>normality</concept>
 </defines>
 <related>
	<object name="HowIsNormalityAndT4DefinedInBooks"/>
	<object name="ApplicationsOfUrysohnsLemmaToLocallyCompactHausdorffSpaces"/>
 </related>
 <keywords>
	<term>topology</term>
 </keywords>
 <preamble>\usepackage{amssymb}
\usepackage{amsmath}
\usepackage{amsfonts}</preamble>
 <content>\PMlinkescapeword{corollary}

A \emph{normal space} is a topological space $X$
such that whenever $A$ and $B$ are disjoint closed subsets of $X$,
then there are disjoint open subsets $U$ and $V$ of $X$
such that $A\subseteq U$ and $B\subseteq V$.

(Note that some authors include $\mathrm{T}_1$ in the definition,
which is equivalent to requiring the space to be Hausdorff.)

\emph{Urysohn's Lemma} states that $X$ is normal
if and only if
whenever $A$ and $B$ are disjoint closed subsets of $X$,
then there is a continuous function $f\colon X\to[0,1]$
such that $f(A)\subseteq\{0\}$ and $f(B)\subseteq\{1\}$.
(Any such function is called an \emph{Urysohn function}.)

A corollary of Urysohn's Lemma
is that normal \PMlinkname{$\mathrm{T}_1$}{T1Space} spaces are completely regular.</content>
</record>
