<?xml version="1.0" encoding="UTF-8"?>

<record version="14" id="1639">
 <title>Hasse diagram</title>
 <name>HasseDiagram</name>
 <created>2002-02-02 03:10:14</created>
 <modified>2004-04-11 15:26:58</modified>
 <type>Definition</type>
 <creator id="348" name="bbukh"/>
 <author id="348" name="bbukh"/>
 <author id="132" name="xriso"/>
 <classification>
	<category scheme="msc" code="05C90"/>
 </classification>
 <related>
	<object name="Poset"/>
	<object name="PartialOrder"/>
 </related>
 <preamble>\usepackage{amssymb}
\usepackage{amsmath}
\usepackage{amsfonts}
\usepackage{xypic}</preamble>
 <content>If $(A,\leq)$ is a finite poset, then it can be represented by a \emph{Hasse diagram}, which is a graph whose vertices are elements of $A$ and the edges correspond to the covering relation. More precisely an edge from $x\in A$ to $y\in A$ is present if
\begin{itemize}
\item $x &lt; y$.
\item There is no $z \in A$ such that $x &lt; z$ and $z &lt; y$. (There are no in-between elements.)
\end{itemize}
If $x&lt;y$, then in $y$ is drawn higher than $x$. Because of that, the direction of the edges is never indicated in a Hasse diagram.

\emph{Example:} If $A = \mathcal{P}(\{1,2,3\})$, the power set of $\{1,2,3\}$, and $\leq$
is the subset relation $\subseteq$, then Hasse diagram is
$$\xymatrix{
                               &amp; \{1,2,3\} &amp;    \\
\{1,2\} \ar@{-}[ur]  &amp; \{1,3\} \ar@{-}[u]  &amp; \{2,3\} \ar@{-}[ul] \\
\{1\} \ar@{-}[u] \ar@{-}[ur] &amp; \{2\} \ar@{-}[ul] \ar@{-}[ur] &amp; \{3\} \ar@{-}[ul] \ar@{-}[u] \\
  &amp; \emptyset \ar@{-}[ul] \ar@{-}[u] \ar@{-}[ur] &amp; }
$$


Even though $\{3\} &lt; \{1,2,3\}$ (since $\{3\} \subset \{1,2,3\}$), there is no edge directly between them because there are inbetween elements:
$\{2,3\}$ and $\{1,3\}$. However, there still remains an indirect path from $\{3\}$ to $\{1,2,3\}$.</content>
</record>
