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<record version="15" id="1700">
 <title>path integral</title>
 <name>PathIntegral</name>
 <created>2002-02-03 00:15:08</created>
 <modified>2007-01-03 07:27:18</modified>
 <type>Definition</type>
 <creator id="78" name="slider142"/>
 <author id="2872" name="pahio"/>
 <author id="409" name="mps"/>
 <author id="78" name="slider142"/>
 <classification>
	<category scheme="msc" code="46T12"/>
	<category scheme="msc" code="81S40"/>
 </classification>
 <synonyms>
	<synonym concept="path integral" alias="line integral"/>
 </synonyms>
 <related>
	<object name="ComplexIntegral"/>
	<object name="ContourIntegral"/>
 </related>
 <keywords>
	<term>integral of a vector field</term>
	<term>integral over a vector field</term>
 </keywords>
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The \emph{path integral} is a generalization of the integral that is very useful in theoretical and applied physics. Consider a vector field $\vec{F}\!:\mathbb{R}^n\rightarrow\mathbb{R}^m$ and a \PMlinkname{path}{PathConnected} $\gamma\subset\mathbb{R}^n$. The path integral of $\vec{F}$ along the path $\gamma$ is defined as a definite integral. It can be constructed to be the Riemann sum of the values of $\vec{F}$ along the curve $\gamma$, aka the area under the curve $S:\gamma\rightarrow\vec{F}$. Thusly, it is defined in terms of the parametrization of $\gamma$, mapped into the domain $\mathbb{R}^n$ of $\vec{F}$. Analytically,
$$\int_\gamma \vec{F}\cdot d\vec{x} = \int_a^b \vec{F}(\vec{\gamma}(t))\cdot d\vec{x}$$
where $\vec{\gamma}(a), \vec{\gamma}(b)$ are elements of $\mathbb{R}^n$, and\, $d\vec{x}=\langle\frac{dx_1}{dt},\cdots,\frac{dx_n}{dt}\rangle dt$\, where each $x_i$ is parametrized into a function of $t$.\\

\textbf{Proof and existence of path integral:}\\
Assume we have a parametrized curve $\vec{\gamma}(t)$ with $t\in[a,b]$. We want to construct a sum of $\vec{F}$ over this interval on the curve $\gamma$. Split the interval $[a,\,b]$ into $n$ subintervals of size $\Delta t=(b-a)/n$. Note that the arc lengths need not be of equal length, though the intervals are of equal size. Let $t_i$ be an element of the $i$th subinterval. The quantity $|\vec{\gamma}'(t_i)|$ gives the average magnitude of the vector tangent to the curve at a point in the interval $\Delta t$. $|\vec{\gamma}'(t_i)|\Delta t$ is then the approximate arc length of the curve segment produced by the subinterval $\Delta t$. Since we want to sum $\vec{F}$ over our curve $\vec{\gamma}$, we let the range of our curve equal the domain of $\vec{F}$. We can then dot this vector with our tangent vector to get the approximation to $\vec{F}$ at the point $\vec{\gamma}(t_i)$. Thus, to get the sum we want, we can take the limit as $\Delta t$ approaches 0.
$$\lim_{\Delta t\rightarrow 0}\sum_a^b \vec{F}(\vec{\gamma}(t_i))\cdot\vec{\gamma}'(t_i)\Delta t$$
This is a Riemann sum, and thus we can write it in integral form. This integral is known as a path or line integral (the older name).
$$\int_\gamma \vec{F}\cdot d\vec{x} = \int_a^b \vec{F}(\vec{\gamma}(t))\cdot\vec{\gamma}'(t)dt$$
Note that the path integral only exists if the definite integral exists on the interval $[a,\,b]$.\\

\textbf{Properties:}\\
A path integral that begins and ends at the same point is called a closed path integral, and is denoted with the summa symbol with a centered circle: $\oint$. These types of path integrals can also be evaluated using Green's theorem.\\
Another property of path integrals is that the directed path integral on a path $\Gamma$ in a vector field is equal to the negative of the path integral in the opposite direction along the same path. A directed path integral on a closed path is denoted by summa and a circle with an arrow denoting direction.\\

\textbf{Visualization Aids:}
\begin{center}
\includegraphics[width=3.65in,height=3.65in]{pintegral}
\end{center}
This is an image of a path $\gamma$ superimposed on a vector field $\vec{F}$.
\begin{center}
\includegraphics[width=4in,height=3in]{bootleg}
\end{center}
This is a visualization of what we are doing when we take the integral under the curve $S:P\rightarrow\vec{F}$.</content>
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