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<record version="4" id="2002">
 <title>almost everywhere</title>
 <name>AlmostSurely</name>
 <created>2002-02-16 10:40:46</created>
 <modified>2004-04-09 11:21:04</modified>
 <type>Definition</type>
 <creator id="2727" name="mathcam"/>
 <author id="2727" name="mathcam"/>
 <author id="72" name="drummond"/>
 <classification>
	<category scheme="msc" code="60A10"/>
 </classification>
 <synonyms>
	<synonym concept="almost everywhere" alias="almost surely"/>
	<synonym concept="almost everywhere" alias="a.s."/>
	<synonym concept="almost everywhere" alias="a.e."/>
	<synonym concept="almost everywhere" alias="almost all"/>
 </synonyms>
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 <content>Let $(X, \borel, \mu)$ be a measure space.  A condition holds \emph{almost everywhere} on $X$ if it holds ``with probability $1$,'' i.e. if it holds everywhere except for a subset of $X$ with measure $0$.  For example, let $f$ and $g$ be nonnegative functions on $X$.  Suppose we want a sufficient condition on functions $f(x)$ and $g(x)$ such that the relation
\begin{equation}
\int_{X} f d\mu(x) \le \int_{X} g d\mu(x) 
\end{equation}
holds.  Certainly $f(x)\leq g(x)$ for all $x\in X$ is a sufficient condition, but in fact it's enough to have $f(x)\leq g(x)$ almost surely on $X$.  In fact, we can loosen the above non-negativity condition to only require that $f$ and $g$ are almost surely nonnegative as well.

If $X = [0,1]$, then $g$ might be less than $f$ on the Cantor set, an uncountable set with measure $0$, and still satisfy the condition.  We say that $f \le g$ almost everywhere (often abbreviated \emph{a.e.}).   

Note that this \PMlinkescapetext{term} is the \PMlinkescapetext{equivalent} of the \PMlinkescapetext{term} ``almost surely'' from probabilistic measure \PMlinkescapetext{theory}.</content>
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