<?xml version="1.0" encoding="UTF-8"?>

<record version="7" id="2262">
 <title>cycle</title>
 <name>Cycle2</name>
 <created>2002-02-19 22:37:23</created>
 <modified>2007-04-30 09:28:44</modified>
 <type>Definition</type>
 <creator id="2760" name="yark"/>
 <author id="2760" name="yark"/>
 <author id="3" name="drini"/>
 <classification>
	<category scheme="msc" code="20F55"/>
	<category scheme="msc" code="05A05"/>
	<category scheme="msc" code="03-00"/>
 </classification>
 <related>
	<object name="Permutation"/>
	<object name="SymmetricGroup"/>
	<object name="Transposition"/>
	<object name="Group"/>
	<object name="Subgroup"/>
	<object name="DihedralGroup"/>
	<object name="CycleNotation"/>
	<object name="PermutationNotation"/>
 </related>
 <preamble>%\usepackage{graphicx}
%\usepackage{xypic} 
\usepackage{bbm}
\newcommand{\Z}{\mathbbmss{Z}}
\newcommand{\C}{\mathbbmss{C}}
\newcommand{\R}{\mathbbmss{R}}
\newcommand{\Q}{\mathbbmss{Q}}
\newcommand{\mathbb}[1]{\mathbbmss{#1}}</preamble>
 <content>Let $S$ be a set. A \emph{cycle} is a permutation
(bijective function of a set onto itself)
such that there exist distinct elements $a_1, a_2,\ldots,a_k$ of $S$
such that
$$f(a_i) = a_{i+1}\qquad \mbox{and}\qquad f(a_k)=a_1$$
that is
\begin{eqnarray*}
f(a_1)&amp;=&amp;a_{2}\\
f(a_{2})&amp;=&amp;a_{3}\\
&amp;\vdots&amp;\\
f(a_{k})&amp;=&amp;a_{1}\\
\end{eqnarray*}
and $f(x)=x$ for any other element of $S$.

This can also be pictured as
$$a_1\mapsto a_{2}\mapsto a_{3}\mapsto\cdots\mapsto a_{k}\mapsto a_{1}$$
and $$x\mapsto x$$ 
for any other element $x\in S$, where $\mapsto$ represents the action of $f$.

One of the basic results on symmetric groups
says that any finite permutation can be expressed as product of disjoint cycles.</content>
</record>
