<?xml version="1.0" encoding="UTF-8"?>

<record version="9" id="2561">
 <title>chain rule</title>
 <name>ChainRule</name>
 <created>2002-02-24 01:50:48</created>
 <modified>2004-09-27 14:57:11</modified>
 <type>Theorem</type>
 <creator id="1858" name="matte"/>
 <author id="1858" name="matte"/>
 <author id="146" name="rmilson"/>
 <classification>
	<category scheme="msc" code="26A06"/>
 </classification>
 <related>
	<object name="Derivative"/>
	<object name="ChainRuleSeveralVariables"/>
	<object name="ExampleOnSolvingAFunctionalEquation"/>
 </related>
 <preamble>\usepackage{amsmath}
\usepackage{amsfonts}
\usepackage{amssymb}

\newcommand{\reals}{\mathbb{R}}
\newcommand{\natnums}{\mathbb{N}}
\newcommand{\cnums}{\mathbb{C}}
\newcommand{\znums}{\mathbb{Z}}

\newcommand{\lp}{\left(}
\newcommand{\rp}{\right)}
\newcommand{\lb}{\left[}
\newcommand{\rb}{\right]}

\newcommand{\supth}{^{\text{th}}}


\newtheorem{proposition}{Proposition}</preamble>
 <content>Let $f, g$ be differentiable,
real-valued functions such that $g$ is defined on an open set 
$I\subseteq \mathbb{R}$, and $f$ is defined on $g(I)$. 
Then the derivative of the composition $f\circ g$ is given by
the \emph{chain rule}, which asserts that
$$
  (f\circ g)'(x) = (f'\circ g)(x)\, g'(x), \quad x\in I.
$$

The chain rule has a particularly suggestive appearance in terms of
the Leibniz formalism.  Suppose that $z$ depends differentiably on
$y$, and that $y$ in turn depends differentiably on $x$.  Then we have
$$
  \frac{dz}{dx} = \frac{dz}{dy}\, \frac{dy}{dx}.
$$
The apparent cancellation  of the $dy$ term is at best a formal
mnemonic, and does not constitute a rigorous proof of this result.
Rather, the Leibniz format is well suited to the interpretation of the
chain rule in terms of related rates. To wit:
\begin{quote}
  \em The instantaneous rate of change of $z$ relative to $x$ is equal to the
  rate of change of $z$ relative to $y$ times the rate of change of
  $y$ relative to $x$.
\end{quote}</content>
</record>
