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<record version="4" id="2658">
 <title>indeterminate form</title>
 <name>IndeterminateForm</name>
 <created>2002-02-25 01:08:15</created>
 <modified>2006-11-11 10:17:52</modified>
 <type>Definition</type>
 <creator id="2" name="akrowne"/>
 <author id="2" name="akrowne"/>
 <classification>
	<category scheme="msc" code="12D99"/>
 </classification>
 <synonyms>
	<synonym concept="indeterminate form" alias="indeterminate value"/>
 </synonyms>
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	<object name="ImproperLimits"/>
	<object name="EmptyProduct"/>
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 <content>The expression

$$ \frac{0}{0} $$

is known as the \emph{indeterminate form}.  The motivation for this name is that there are no rules for comparing the value of $\frac{0}{0}$ to the other real numbers.  Note that, for example, $\frac{1}{0}$ is \emph{not} indeterminate, since we can justifiably associate it with $+\infty$, which \emph{does} compare with the rest of the real numbers (in particular, it is defined to be greater than all of them.)

\section{Other Indeterminate Forms}

Although $\frac{0}{0}$ is often called ``the'' indeterminate form, there are many others.  Some of these are:

\begin{enumerate} 

\item $ \frac{\infty}{\infty} $, for the same motivating reasons as $\frac{0}{0}$.

\item $ 0^0 $; which is the result of much impassioned debate (especially since $0!$ is defined to be 1, counter-intuitively, but not unreasonably).

\item $1^{\infty}$; notably because of the derivation of $e$: 

$$ \lim_{n \to \infty} \left( 1+\frac{1}{n} \right)^n = e $$

A direct substitution would yield $1^\infty$.

\end{enumerate}</content>
</record>
