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<record version="10" id="2723">
 <title>$\sigma$-finite</title>
 <name>SigmaFinite</name>
 <created>2002-02-27 00:29:13</created>
 <modified>2006-09-13 22:16:45</modified>
 <type>Definition</type>
 <creator id="127" name="Koro"/>
 <author id="127" name="Koro"/>
 <author id="72" name="drummond"/>
 <classification>
	<category scheme="msc" code="28A10"/>
 </classification>
 <defines>
	<concept>$\sigma$-infinite</concept>
	<concept>sigma-infinite</concept>
	<concept>finite measure space</concept>
 </defines>
 <synonyms>
	<synonym concept="$\sigma$-finite" alias="$\sigma$ finite"/>
	<synonym concept="$\sigma$-finite" alias="sigma-finite"/>
	<synonym concept="$\sigma$-finite" alias="sigma finite"/>
 </synonyms>
 <related>
	<object name="Measure"/>
	<object name="MeasureSpace"/>
	<object name="AlternativeDefinitionOfSigmaFiniteMeasure"/>
	<object name="AnySigmaFiniteMeasureIsEquivalentToAProbabilityMeasure"/>
 </related>
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 <content>\PMlinkescapeword{finite}
\PMlinkescapeword{infinite}
A measure space $(\Omega, \mathcal{B}, \mu)$ is a \textbf{finite measure space} if $\mu(\Omega)&lt;\infty$; it is $\sigma$-\textbf{finite} if the total space is the union of a finite or countable family of sets of finite measure, i.e. if there exists a countable set $\mathcal{F}\subset \mathcal{B}$ such that $\mu(A)&lt;\infty$ for each $A\in \mathcal{F}$, and
$\Omega=\bigcup_{A\in\mathcal{F}} A.$
In this case we also say that $\mu$ is a $\sigma$-finite measure.
If $\mu$ is not $\sigma$-finite, we say that it is $\sigma$-\textbf{infinite}.

\textbf{Examples.} Any finite measure space is $\sigma$-finite. A more interesting example is the Lebesgue measure $\mu$ in $\mathbb{R}^n$: it is $\sigma$-finite but not finite. In fact $$\mathbb{R}^n=\bigcup_{k\in\mathbb{N}} [-k,k]^n$$ ($[-k,k]^n$ is a cube with center at $0$ and side length $2k$, and its measure is $(2k)^n$), but $\mu(\mathbb{R}^n)=\infty$.</content>
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