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<record version="6" id="2749">
 <title>maximal element</title>
 <name>MaximalElement</name>
 <created>2002-03-02 13:28:20</created>
 <modified>2006-10-28 23:16:56</modified>
 <type>Definition</type>
 <creator id="2" name="akrowne"/>
 <author id="2" name="akrowne"/>
 <classification>
	<category scheme="msc" code="03E04"/>
 </classification>
 <defines>
	<concept>greatest element</concept>
	<concept>least element</concept>
	<concept>minimal element</concept>
 </defines>
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 <content>Let $\le$ be an ordering on a set $S$, and let $A \subseteq S$. Then, with respect  to the ordering $\le$, 

\begin{itemize}

\item $a \in A$ is the \emph{least} element of $A$ if $a \le x$, for all $x \in A$.
\item $a \in A$ is a \emph{minimal} element of $A$ if there exists no $x \in A$ such that $x \le a$ and $x \ne a$.
\item $a \in A$ is the \emph{greatest} element of $A$ if $x \le a$ for all $x \in A$.
\item $a \in A$ is a \emph{maximal} element of $A$ if there exists no $x \in A$ such that $a \le x$ and $x \ne a$.

\end{itemize}

\paragraph{Examples.}

\begin{itemize}
\item The natural numbers $\mathbb{N}$ ordered by divisibility ($\mid$) have a least element, $1$.  The natural numbers greater than 1 ($\mathbb{N} \setminus \{1\}$) have no least element, but infinitely many minimal elements (the primes.)  In neither case is there a greatest or maximal element.
\item  The negative integers ordered by the standard definition of $\le$ have a  maximal element which is also the greatest element, $-1$.  They have no minimal or least element.
\item The natural numbers $\mathbb{N}$ ordered by the standard $\le$ have a least element, $1$, which is also a minimal element.  They have no greatest or maximal element.  
\item The rationals greater than zero with the standard ordering $\le$ have no least element or minimal element, and no maximal or greatest element.
\end{itemize}</content>
</record>
