<?xml version="1.0" encoding="UTF-8"?>

<record version="2" id="277">
 <title>Chebyshev's inequality</title>
 <name>ChebyshevsInequality</name>
 <created>2001-10-17 01:28:42</created>
 <modified>2006-12-11 23:48:06</modified>
 <type>Theorem</type>
 <creator id="3" name="drini"/>
 <author id="6075" name="rspuzio"/>
 <author id="3" name="drini"/>
 <classification>
	<category scheme="msc" code="26D15"/>
 </classification>
 <related>
	<object name="RearrangementInequality"/>
	<object name="ProofOfRearrangementInequality"/>
	<object name="KolmogorovsInequality"/>
	<object name="ChebyshevsInequality2"/>
 </related>
 <keywords>
	<term>Inequality</term>
 </keywords>
 <preamble>\usepackage{amssymb}
\usepackage{amsmath}
\usepackage{amsfonts}
\usepackage{graphicx}
\usepackage{xypic}
</preamble>
 <content>If $x_1,x_2,\ldots,x_n$ and $y_1,y_2,\ldots,y_n$ are two sequences (at least one of them consisting of positive numbers):
\begin{itemize}
\item if $x_1&lt;x_2&lt;\cdots&lt;x_n$ and $y_1&lt;y_2&lt;\cdots&lt;y_n$ then$$\left(\frac{x_1+x_2+\cdots+x_n}{n}\right)\left(\frac{y_1+y_2+\cdots+y_n}{n}\right)
\le\frac{x_1y_1+x_2y_2+\cdots+x_ny_n}{n}.$$
\item if $x_1&lt;x_2&lt;\cdots&lt;x_n$ and $y_1&gt;y_2&gt;\cdots&gt;y_n$ then$$\left(\frac{x_1+x_2+\cdots+x_n}{n}\right)\left(\frac{y_1+y_2+\cdots+y_n}{n}\right)
\ge\frac{x_1y_1+x_2y_2+\cdots+x_ny_n}{n}.$$\end{itemize}</content>
</record>
