sines lawSinesLaw2001-08-18 21:55:092002-01-30 20:06:05TheoremSineTrigonometryCircleCircumcircleTriangle\usepackage{amssymb}
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\textbf{Sines Law.}\\
Let $ABC$ be a triangle where $a,b,c$ are the sides opposite to $A,B,C$ respectively, and let $R$ be the radius of the circumcircle. Then the following relation holds:
$$\frac{a}{\sin A}=\frac{b}{\sin B}=\frac{c}{\sin C}=2R.$$
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