<?xml version="1.0" encoding="UTF-8"?>

<record version="12" id="2873">
 <title>normalizer</title>
 <name>Normalizer</name>
 <created>2002-04-25 17:22:36</created>
 <modified>2007-08-22 08:10:09</modified>
 <type>Definition</type>
 <creator id="2760" name="yark"/>
 <author id="2760" name="yark"/>
 <author id="11260" name="cvalente"/>
 <author id="225" name="saforres"/>
 <classification>
	<category scheme="msc" code="20A05"/>
 </classification>
 <defines>
	<concept>self-normalizing</concept>
 </defines>
 <synonyms>
	<synonym concept="normalizer" alias="normaliser"/>
 </synonyms>
 <related>
	<object name="Centralizer"/>
	<object name="NormalSubgroup"/>
	<object name="NormalClosure2"/>
 </related>
 <preamble>\usepackage{amssymb}
\usepackage{amsmath}
\usepackage{amsfonts}
</preamble>
 <content>\section*{Definitions}

Let $G$ be a group, and let $H \subseteq G$.
The {\em normalizer} of $H$ in $G$, written $N_G(H)$, is the set
\[
  \{ g \in G \mid gHg^{-1}=H \}.
\]

A subgroup $H$ of $G$ is said to be {\em self-normalizing} if $N_G(H) = H$.

\section*{Properties}

$N_G(H)$ is always a subgroup of $G$,
as it is the stabilizer of $H$ under the action $(g,H)\mapsto gHg^{-1}$
of $G$ on the set of all subsets of $G$
(or on the set of all subgroups of $G$, if $H$ is a subgroup).

If $H$ is a subgroup of $G$, then $H\leq N_G(H)$.

If $H$ is a subgroup of $G$, then $H$ is a normal subgroup of $N_G(H)$;
in fact, $N_G(H)$ is the largest subgroup of $G$
of which $H$ is a normal subgroup.
In particular, if $H$ is a subgroup of $G$,
then $H$ is normal in $G$ if and only if $N_G(H)=G$.</content>
</record>
