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 <title>completion</title>
 <name>Completion</name>
 <created>2002-05-21 17:30:51</created>
 <modified>2005-08-21 04:37:08</modified>
 <type>Definition</type>
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 <author id="24" name="djao"/>
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 <content>Let $(X,d)$ be a metric space. Let $\bar{X}$ be the set of all Cauchy
sequences $\{x_n\}_{n \in \N}$ in $X$. Define an equivalence relation
$\sim$ on $\bar{X}$ by setting $\{x_n\} \sim \{y_n\}$ if the
interleave sequence of the sequences $\{x_n\}$ and $\{y_n\}$ is also a
Cauchy sequence. The {\em completion} of $X$ is defined to be the set
$\hat{X}$ of equivalence classes of $\bar{X}$ modulo $\sim$.

The metric $d$ on $X$ extends to a metric on $\hat{X}$ in the
following manner:
$$
d(\{x_n\},\{y_n\}) := \lim_{n \to \infty} d(x_n,y_n),
$$
where $\{x_n\}$ and $\{y_n\}$ are representative Cauchy sequences of
elements in $\hat{X}$. The definition of $\sim$ is tailored so that
the limit in the above definition is well defined, and the fact that these
sequences are Cauchy, together with the fact that $\R$ is complete,
ensures that the limit exists. The space $\hat{X}$ with this metric is of course a complete metric space.

The original metric space $X$ is isometric to the subset of $\hat{X}$ consisting of equivalence classes of constant sequences.

Note the similarity between the construction of $\hat{X}$ and the
construction of $\R$ from $\Q$. The process used here is the same as
that used to construct the real numbers $\R$, except for the minor
detail that one can not use the terminology of metric spaces in the
construction of $\R$ itself because it is necessary to construct $\R$
in the first place before one can define metric spaces.

\section{Metric spaces with richer structure}

If the metric space $X$ has an algebraic structure, then in many
cases this algebraic structure carries through unchanged to $\hat{X}$
simply by applying it one element at a time to sequences in $X$. We
will not attempt to state this principle precisely, but we will
mention the following important instances:

\begin{enumerate}
\item If $(X,\cdot)$ is a topological group, then $\hat{X}$ is also a
  topological group with multiplication defined by
$$
\{x_n\} \cdot \{y_n\} = \{x_n \cdot y_n\}.
$$
\item If $X$ is a topological ring, then addition and multiplication
  extend to $\hat{X}$ and make the completion into a topological ring.
\item If $F$ is a field with a valuation $v$, then the completion of
  $F$ with respect to the metric imposed by $v$ is a topological
  field, denoted $F_v$ and called the completion of $F$ at $v$.
\end{enumerate}

\section{Universal property of completions}

The completion $\hat{X}$ of $X$ satisfies the following universal property: for every uniformly continuous map $f: X \lra Y$ of $X$ into a complete metric space $Y$, there exists a unique lifting of $f$ to a continuous map $\hat{f}: \hat{X} \lra Y$ making the diagram
$$
\xymatrix{
X \ar[rr]^f \ar[dr] &amp; &amp; Y \\
&amp; \hat{X} \ar[ur]_{\hat{f}}
}
$$
commute. Up to isomorphism, the completion of $X$ is the unique metric space satisfying this property. The ability to extend uniformly continuous functions from $X$ to $\hat{X}$ is often the reason why algebraic structures on $X$ extend to $\hat{X}$ as described in the previous section.</content>
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