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<record version="10" id="3024">
 <title>Baire category theorem</title>
 <name>BaireCategoryTheorem</name>
 <created>2002-06-04 07:41:44</created>
 <modified>2004-09-29 11:27:00</modified>
 <type>Theorem</type>
 <creator id="127" name="Koro"/>
 <author id="127" name="Koro"/>
 <author id="338" name="ariels"/>
 <classification>
	<category scheme="msc" code="54E52"/>
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 <related>
	<object name="SardsTheorem"/>
	<object name="Meager"/>
	<object name="Residual"/>
 </related>
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 <content>In a non-empty complete metric space, any countable intersection of dense, open subsets is non-empty.

In fact, such countable intersections of dense, open subsets are dense.  So the theorem holds also for any non-empty open subset of a complete metric space.

\textbf{Alternative formulations:}
Call a set \emph{first category}, or a \emph{meagre} set, if it is a countable union of nowhere dense sets, otherwise \emph{second category}. The Baire category theorem is often stated as ``no non-empty complete metric space is of first category'', or, trivially, as ``a non-empty, complete metric space is of second category''. In short, this theorem says that every nonempty complete metric space is a Baire space.

In functional analysis, this important property of complete metric spaces forms the {b}asis for the proofs of the important principles of Banach spaces: the open mapping theorem and the closed graph theorem.

It may also be taken as giving a concept of ``small sets'', similar to sets of measure zero: a countable union of these sets remains ``small''.  However, the real line $\mathbb{R}$ may be partitioned into a set of measure zero and a set of first category; the two concepts are distinct.

Note that, apart from the requirement that the set be a complete metric space, all conditions and conclusions of the theorem are phrased topologically.  This ``metric requirement'' is thus something of a disappointment.  As it turns out, there are two ways to reduce this requirement.

First, if a topological space $\mathcal{T}$ is homeomorphic to a non-empty open subset of a complete metric space, then we can transfer the Baire property through the homeomorphism, so in $\mathcal{T}$ too any countable intersection of open dense sets is non-empty (and, in fact, dense).  The other formulations also hold in this case.

Second, the Baire category theorem holds for a locally compact, Hausdorff\footnote{Some authors only define a locally compact space to be a Hausdorff space; that is the sense required for this theorem.} topological space  $\mathcal{T}$.</content>
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