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<record version="6" id="3128">
 <title>conjecture on fractions with odd denominators</title>
 <name>AnyRationalNumberWithOddDenominatorIsASumOfUnitFractionsWithOddDenominators</name>
 <created>2002-06-23 06:42:58</created>
 <modified>2007-09-14 03:52:49</modified>
 <type>Conjecture</type>
<parent id="3127">any rational number is a sum of unit fractions</parent>
 <creator id="3" name="drini"/>
 <author id="2872" name="pahio"/>
 <author id="348" name="bbukh"/>
 <author id="3" name="drini"/>
 <author id="338" name="ariels"/>
 <classification>
	<category scheme="msc" code="11A67"/>
	<category scheme="msc" code="11D68"/>
 </classification>
 <related>
	<object name="SierpinskiErdosEgyptianFractionConjecture"/>
 </related>
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\newtheorem{conjecture}{Conjecture}</preamble>
 <content>Egyptian fractions raise many open problems; this is one of the most famous of them.

Suppose we wish to write fractions as sums of distinct unit fractions \emph{with odd denominators}.  Obviously, every such sum will have a reduced representation with an odd denominator.

For instance, the greedy algorithm applied to $\frac{2}{7}$ gives $\frac{1}{4}+\frac{1}{28}$, but we may also write $\frac{2}{7}$ as $\frac{1}{7}+\frac{1}{9}+\frac{1}{35}+\frac{1}{315}$.

It is known that we can we represent \emph{every} rational number with odd denominator as a sum of distinct unit fractions with odd denominators.

However it is not known whether the \PMlinkname{greedy algorithm}{AnyRationalNumberIsASumOfUnitFractions} works when limited to odd denominators.  

\begin{conjecture}
For any fraction $0\le \frac{a}{2k+1} &lt; 1$ with odd denominator, if we repeatedly subtract the largest unit fraction with odd denominator that is smaller than our fraction, we will eventually reach 0.
\end{conjecture}</content>
</record>
