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<record version="14" id="3176">
 <title>measurable function</title>
 <name>MeasurableFunctions</name>
 <created>2002-07-21 15:02:26</created>
 <modified>2006-12-09 02:33:55</modified>
 <type>Definition</type>
 <creator id="3771" name="CWoo"/>
 <author id="3771" name="CWoo"/>
 <author id="40" name="Daume"/>
 <author id="449" name="vypertd"/>
 <classification>
	<category scheme="msc" code="28A20"/>
 </classification>
 <defines>
	<concept>Borel measurable function</concept>
 </defines>
 <synonyms>
	<synonym concept="measurable function" alias="Borel measurable"/>
 </synonyms>
 <related>
	<object name="ExampleOfFunctionNotLebesgueMeasurableWithMeasurableLevelSets"/>
	<object name="LusinsTheorem2"/>
	<object name="BorelGroupoid"/>
	<object name="BorelMorphism"/>
 </related>
 <keywords>
	<term>measurable</term>
 </keywords>
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 <content>Let $\big(X,\mathcal{B}(X)\big)$ and $\big(Y, \mathcal{B}(Y)\big)$ be two measurable spaces.  Then a function $f\colon X\to Y$ is called a \emph{measurable function} if:
$$f^{-1}\big(\mathcal{B}(Y)\big) \subseteq \mathcal{B}(X)$$
where $f^{-1}\big(\mathcal{B}(Y)\big) = \{f^{-1}(E)\mid E\in\mathcal{B}(Y)\}$.\\  

In other words,  the inverse image of every $\mathcal{B}(Y)$-measurable set is $\mathcal{B}(X)$-measurable.  The space of all measurable functions $f\colon X\to Y$ is denoted as $$\mathcal{M}\big(\big(X,\mathcal{B}(X)\big),\big(Y, \mathcal{B}(Y)\big)\big).$$  Any measurable function into $(\mathbb{R},\mathcal{B}(\mathbb{R}))$, where $\mathcal{B}(\mathbb{R})$ is the Borel sigma algebra of the real numbers $\mathbb{R}$, is called a \emph{Borel measurable function}.{\footnote {More generally, a measurable function is called \emph{Borel measurable} if the range space $Y$ is a topological space with $\mathcal{B}(Y)$ the sigma algebra generated by all open sets of $Y$.}}   The space of all Borel measurable functions from a measurable space $(X,\mathcal{B}(X))$ is denoted by  $\displaystyle{\mathcal{L}^0\big(X,\mathcal{B}(X)\big)}$.  

Similarly, we write $\displaystyle{\bar{\mathcal{L}}^0\big(X,\mathcal{B}(X)\big)}$ for  $\displaystyle{\mathcal{M}\big(\big(X,\mathcal{B}(X)), (\bar{\mathbb{R}},\mathcal{B}(\bar{\mathbb{R}})\big)\big)}$, where $\mathcal{B}(\bar{\mathbb{R}})$ is the Borel sigma algebra of $\bar{\mathbb{R}}$, the set of extended real numbers. \\

\textbf{Remark}.  If $f:X\to Y$ and $g:Y\to Z$ are measurable functions, then so is $g\circ f:X\to Z$, for if $E$ is $\mathcal{B}(Z)$-measurable, then $g^{-1}(E)$ is $\mathcal{B}(Y)$-measurable, and $f^{-1}\big(g^{-1}(E)\big)$ is $\mathcal{B}(X)$-measurable.  But $f^{-1}\big(g^{-1}(E)\big)=(g\circ f)^{-1}(E)$, which implies that $g\circ f$ is a measurable function.

\textbf{Example:}
\begin{itemize}
\item Let $E$ be a subset of a measurable space $X$ then the characteristic function $\chi_E$ is a measurable function if and only if $E$ is measurable.
\end{itemize}</content>
</record>
