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<record version="19" id="3278">
 <title>M\"obius strip</title>
 <name>MobiusStrip</name>
 <created>2002-08-08 03:02:41</created>
 <modified>2006-10-02 13:40:35</modified>
 <type>Definition</type>
 <creator id="13753" name="Mathprof"/>
 <author id="13753" name="Mathprof"/>
 <author id="3" name="drini"/>
 <author id="96" name="dublisk"/>
 <classification>
	<category scheme="msc" code="54B15"/>
 </classification>
 <synonyms>
	<synonym concept="M\&quot;obius strip" alias="M\&quot;obius band"/>
 </synonyms>
 <related>
	<object name="KleinBottle"/>
	<object name="Torus"/>
 </related>
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 <content>A \emph{M\"{o}bius strip} is a non-orientiable 2-dimensional surface with a 1-dimensional boundary. It can be embedded in $\mathbb{R}^3$, but only has a single \PMlinkescapetext{side}.

We can parameterize the M\"{o}bius strip by
\[
x = r \cdot \cos{\theta}, \quad y = r \cdot \sin{\theta}, \quad z =
(r-2)\tan{\frac{\theta}{2}}.
\]
The M\"{o}bius strip is therefore a subset of the solid torus.

Topologically, the M\"{o}bius strip  is formed by taking a quotient space of $I^2 = [0,1] \times [0,1] \subset \mathbb{R}^2$. We do this by first letting $M$ be the partition of $I^2$ formed by the equivalence relation:
$$(1,x) \sim (0,1-x)\quad \mbox{where} \quad 0 \leq x \leq 1,$$ and every other point in $I^2$ is only related to itself.

By giving $M$ the quotient topology given by the quotient map $p: I^2 \to  M$ we obtain the M\"{o}bius strip.

Schematically we can represent this identification as follows:

\begin{center}
\includegraphics[scale=0.5]{mobius-2} \\
\tiny{Diagram 1: The identifications made on $I^2$ to make a M\"{o}bius strip. \\ We identify two opposite sides but with different orientations.}
\end{center}

Since the M\"{o}bius strip is homotopy equivalent to a circle, it has $\mathbb{Z}$\ as its fundamental group. It is not however, homeomorphic to the circle, although its boundary is.</content>
</record>
