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<record version="4" id="3350">
 <title>Knuth's up arrow notation</title>
 <name>KnuthsUpArrowNotation</name>
 <created>2002-08-24 19:53:03</created>
 <modified>2004-05-10 13:42:34</modified>
 <type>Definition</type>
 <creator id="455" name="Henry"/>
 <author id="455" name="Henry"/>
 <classification>
	<category scheme="msc" code="00A05"/>
 </classification>
 <synonyms>
	<synonym concept="Knuth's up arrow notation" alias="up-arrow"/>
	<synonym concept="Knuth's up arrow notation" alias="up arrow"/>
	<synonym concept="Knuth's up arrow notation" alias="up-arrow notation"/>
	<synonym concept="Knuth's up arrow notation" alias="up arrow notation"/>
	<synonym concept="Knuth's up arrow notation" alias="Knuth notation"/>
 </synonyms>
 <related>
	<object name="ConwaysChainedArrowNotation"/>
 </related>
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 <content>\emph{Knuth's up arrow noation} is a way of writing numbers which would be unwieldy in standard decimal notation.  It expands on the exponential notation $m\uparrow n=m^n$.  Define $m\uparrow\uparrow 0=1$ and $m \uparrow\uparrow n=m\uparrow(m\uparrow\uparrow [n-1])$.

Obviously $m\uparrow\uparrow 1=m^1=m$, so $3\uparrow\uparrow 2=3^{3\uparrow\uparrow 1}=3^3=27$, but $2\uparrow\uparrow 3=2^{2 \uparrow\uparrow 2}=2^{2^{2\uparrow\uparrow 1}}=2^{(2^2)}=16$.

In general, $m\uparrow\uparrow n=m^{m^{\cdots^m}}$, a tower of height $n$.

Clearly, this process can be extended: $m\uparrow\uparrow\uparrow 0=1$ and $m\uparrow\uparrow\uparrow n=m\uparrow\uparrow(m\uparrow\uparrow\uparrow [n-1])$.

An alternate notation is to write $m^{(i)}n$ for $m\underbrace{\uparrow\cdots\uparrow}_{i-2 \text{~times}}n$.  ($i-2$ times because then $m^{(2)}n=m\cdot n$ and $m^{(1)}n=m+n$.)  Then in general we can define $m^{(i)}n=m^{(i-1)}(m^{(i)}(n-1))$.

To get a sense of how quickly these numbers grow, $3\uparrow\uparrow\uparrow 2=3\uparrow\uparrow 3$ is more than seven and a half trillion, and the numbers continue to grow much more than exponentially.</content>
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