<?xml version="1.0" encoding="UTF-8"?>

<record version="5" id="3468">
 <title>Jacobi identity interpretations</title>
 <name>JacobiIdentityInterpretations</name>
 <created>2002-09-20 11:52:22</created>
 <modified>2007-04-01 00:26:48</modified>
 <type>Definition</type>
<parent id="1113">Lie algebra</parent>
 <creator id="6075" name="rspuzio"/>
 <author id="6075" name="rspuzio"/>
 <author id="12020" name="Lando47"/>
 <author id="715" name="draisma"/>
 <classification>
	<category scheme="msc" code="17B99"/>
 </classification>
 <preamble>\usepackage{amssymb}
\usepackage{amsmath}
\usepackage{amsfonts}
\newcommand{\ad}{\operatorname{ad}}
\newcommand{\End}{\operatorname{End}}</preamble>
 <content>The Jacobi identity in a Lie algebra $\mathfrak{g}$ has various interpretations that are more transparent, whence easier to remember, than the usual form
\[ [x,[y,z]]+[y,[z,x]]+[z,[x,y]]=0. \]
One is the fact that the adjoint representation 
\footnote{Here, ``$\mathfrak{gl}(\mathfrak{g})$'' means the space o
endomorphisms of $\mathfrak{g}$, viewed as a vector space, with Lie
bracket on $\mathfrak{gl}(\mathfrak{g})$being commutator.}
$\ad:\mathfrak{g} \rightarrow \mathfrak{gl}(\mathfrak{g})$ really is a representation. Yet another way to formulate the identity is 
\[ \ad(x)[y,z]=[\ad(x)y,z]+[y,\ad(x)z], \]
i.e., $\ad(x)$ is a derivation on $\mathfrak{g}$ for all $x \in \mathfrak{g}$.</content>
</record>
