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<record version="3" id="3559">
 <title>cyclic semigroup</title>
 <name>CyclicSemigroup</name>
 <created>2002-11-01 19:29:43</created>
 <modified>2002-11-02 20:06:30</modified>
 <type>Definition</type>
 <creator id="549" name="mclase"/>
 <author id="549" name="mclase"/>
 <classification>
	<category scheme="msc" code="20M99"/>
 </classification>
 <defines>
	<concept>index</concept>
	<concept>period</concept>
 </defines>
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 <content>A semigroup which is generated by a single element is called a \emph{cyclic semigroup}.

Let $S = \langle x \rangle$ be a cyclic semigroup.  Then as a set, $S = \{ x^n \mid n &gt; 0\}$.

If all powers of $x$ are distinct, then $S = \{x, x^2, x^3, \dotsc \}$ is (countably) infinite.

Otherwise, there is a least integer $n &gt; 0$ such that $x^n = x^m$ for some $m &lt; n$.  It is clear then that the elements $x, x^2, \dots, x^{n-1}$ are distinct, but that for any $j \ge n$, we must have $x^j = x^i$ for some $i$, $m \le i \le n-1$.  So $S$ has $n-1$ elements.

Unlike in the group case, however, there are in general multiple non-isomorphic cyclic semigroups with the same number of elements.  In fact, there are $t$ non-isomorphic cyclic semigroups with $t$ elements:  these correspond to the different choices of $m$ in the above (with $n = t+1$).

The integer $m$ is called the \emph{index} of $S$, and $n-m$ is called the \emph{period} of $S$.

The elements $K = \{x^m, x^{m+1}, \dots, x^{n-1}\}$ are a subsemigroup of $S$.  In fact, $K$ is a cyclic group.

A concrete representation of the semigroup with index $m$ and period $r$ as a semigroup of transformations can be obtained as follows.  Let $X = \{1, 2, 3, \dots, m + r\}$.  Let
$$
\phi =
\begin{pmatrix}
1 &amp; 2 &amp; 3 &amp; \dots &amp; m+r-1 &amp; m+r \\
2 &amp; 3 &amp; 4 &amp; \dots &amp; m+r &amp; r+1
\end{pmatrix}.
$$

Then $\phi$ generates a subsemigroup $S$ of the full semigroup of transformations $\mathcal{T}_X$, and $S$ is cyclic with index $m$ and period $r$.</content>
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