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<record version="6" id="3626">
 <title>skew-symmetric bilinear form</title>
 <name>SkewSymmetricBilinearForm</name>
 <created>2002-11-28 07:33:27</created>
 <modified>2006-02-22 23:21:05</modified>
 <type>Definition</type>
 <creator id="997" name="sleske"/>
 <author id="3771" name="CWoo"/>
 <author id="9427" name="hgilde"/>
 <author id="997" name="sleske"/>
 <classification>
	<category scheme="msc" code="15A63"/>
 </classification>
 <defines>
	<concept>skew symmetric</concept>
	<concept>anti-symmetric</concept>
	<concept>antisymmetric</concept>
 </defines>
 <synonyms>
	<synonym concept="skew-symmetric bilinear form" alias="antisymmetric bilinear form"/>
	<synonym concept="skew-symmetric bilinear form" alias="anti-symmetric bilinear form"/>
 </synonyms>
 <related>
	<object name="AntiSymmetric"/>
	<object name="SymmetricBilinearForm"/>
	<object name="BilinearForm"/>
 </related>
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 <content>A {\em skew-symmetric} (or {\em antisymmetric}) {\em bilinear form} is a special case of a bilinear form $B$, namely one which is skew-symmetric in the two coordinates; that is, $B(x,y) = -B(y,x)$ for all vectors $x$ and $y$. Note that this definition only makes sense if $B$ is defined over two identical vector spaces, so we must require this in the formal definition:

a bilinear form $B: V \times V \rightarrow K$ ($V$ a vector
space over a field $K$) is called {\em skew-symmetric} iff
\begin{quote}
$B(x,y) = -B(y,x)$ for all vectors $x, y \in V$.
\end{quote}

Suppose that the characteristic of $K$ is not $2$.  Set $x=y$ in the above equation.  Then $B(x,x)=-B(x,x)$ for all vectors $x \in V$, which means that $2B(x,x)=0$, or $B(x,x)=0$.  Therefore, $B$ is an alternating form.

If, however, $\operatorname{char}(K)=2$, then $B(x,y)=-B(y,x)=B(y,x)$; $B$ is a symmetric bilinear form.

If $V$ is finite-dimensional, then every bilinear form on $V$ can be represented
by a matrix. In this case the following theorem applies:

A bilinear form is skew-symmetric iff its representing matrix is skew-symmetric.
(The fact that the representing matrix is skew-symmetric is independent of the
choice of representing matrix).</content>
</record>
