<?xml version="1.0" encoding="UTF-8"?>

<record version="6" id="365">
 <title>module</title>
 <name>Module</name>
 <created>2001-10-19 01:20:05</created>
 <modified>2004-11-19 20:55:35</modified>
 <type>Definition</type>
 <creator id="24" name="djao"/>
 <author id="24" name="djao"/>
 <classification>
	<category scheme="msc" code="13-00"/>
	<category scheme="msc" code="16-00"/>
	<category scheme="msc" code="20-00"/>
 </classification>
 <synonyms>
	<synonym concept="module" alias="left module"/>
	<synonym concept="module" alias="right module"/>
 </synonyms>
 <related>
	<object name="MaximalIdeal"/>
	<object name="VectorSpace"/>
 </related>
 <preamble>\usepackage{amssymb}
\usepackage{amsmath}
\usepackage{amsfonts}
\usepackage{graphicx}
\usepackage{xypic}
\renewcommand{\u}{\mathbf{u}}
\renewcommand{\v}{\mathbf{v}}
\newcommand{\w}{\mathbf{w}}
\newcommand{\0}{\mathbf{0}}</preamble>
 <content>Let $R$ be a ring with identity. A {\em left module} $M$ over $R$ is a set with two binary operations, $+: M\times M \longrightarrow M$ and $\cdot: R \times M \longrightarrow M$, such that
\begin{enumerate}
\item $(\u+\v)+\w = \u+(\v+\w)$ for all $\u,\v,\w \in M$
\item $\u+\v=\v+\u$ for all $\u,\v\in M$
\item There exists an element $\0 \in M$ such that $\u+\0=\u$ for all $\u \in M$
\item For any $\u \in M$, there exists an element $\v \in M$ such that $\u+\v=\0$
\item $a \cdot (b \cdot \u) = (a \cdot b) \cdot \u$ for all $a,b \in R$ and $\u \in M$
\item $a \cdot (\u+\v) = (a \cdot \u) + (a \cdot \v)$ for all $a \in R$ and $\u,\v \in M$
\item $(a + b) \cdot \u = (a \cdot \u) + (b \cdot \u)$ for all $a,b \in R$ and $\u \in M$
\end{enumerate}

A left module $M$ over $R$ is called \emph{unitary} or \emph{unital} if $1_R \cdot \u = \u$ for all $\u \in M$.

A (unitary or unital) \emph{right module} is defined analogously, except that the function $\cdot$ goes from $M \times R$ to $M$ and the scalar multiplication operations act on the right. If $R$ is commutative, there is an equivalence of categories between the category of left $R$--modules and the category of right $R$--modules.</content>
</record>
