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<record version="10" id="3776">
 <title>tensor algebra</title>
 <name>TensorAlgebra</name>
 <created>2002-12-18 18:12:33</created>
 <modified>2007-03-22 06:12:53</modified>
 <type>Definition</type>
 <creator id="146" name="rmilson"/>
 <author id="146" name="rmilson"/>
 <author id="13753" name="Mathprof"/>
 <author id="988" name="bwebste"/>
 <classification>
	<category scheme="msc" code="15A69"/>
 </classification>
 <defines>
	<concept>tensor power</concept>
 </defines>
 <related>
	<object name="FreeAssociativeAlgebra"/>
 </related>
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% it should be fine as is for beginners.

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\usepackage{amssymb}
\usepackage{amsmath}
\usepackage{amsfonts}
\newcommand{\mc}[1]{\mathcal{#1}}</preamble>
 <content>Let $R$ be a commutative ring, and $M$ an $R$-module.
The \emph{tensor algebra}
\[ \mc{T}(M) = \bigoplus_{n=0}^\infty \mc{T}_n(M)\]
is the  graded $R$-algebra with $n^{th}$
graded component simply the $n^{th}$ tensor power:
\[ \mc{T}_n(M) = M^{\otimes n} =\overbrace{M\otimes \cdots \otimes
  M}^{n\text{ times}},\quad n=1,2,\ldots,\]
and $\mc{T}_0(M)=R$.
The multiplication $m:\mc{T}(M)\times \mc{T}(M)\to\mc{T}(M)$ is given
by the usual tensor product: 
\[ m(a,b)=a\otimes b,\quad a\in M^{\otimes n},\; b\in M^{\otimes m}.\]

\paragraph{Remark 1.} One can  generalize the above definition to
cover the case where the ground ring $R$ is non-commutative by
requiring that the module $M$ is a bimodule with $R$ acting on both
the left and the right.


\paragraph{Remark 2.} From the point of view of category theory, one
can describe the tensor algebra construction as  a functor $\mc{T}$
from the category of $R$-module to the category of $R$-algebras that
is left-adjoint to the forgetful functor $\mc{F}$ from algebras to
modules.  Thus, for $M$ an $R$-module and $S$ an $R$-algebra, every
module homomorphism $M\to \mc{F}(S)$ extends to a unique algebra
homomorphism $\mc{T}(M)\to S$.</content>
</record>
