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<record version="3" id="4071">
 <title>transversality</title>
 <name>Transversality</name>
 <created>2003-03-02 18:48:06</created>
 <modified>2003-07-25 18:14:20</modified>
 <type>Definition</type>
 <creator id="2727" name="mathcam"/>
 <author id="2727" name="mathcam"/>
 <author id="330" name="gabor_sz"/>
 <classification>
	<category scheme="msc" code="57R99"/>
 </classification>
 <defines>
	<concept>transversal</concept>
	<concept>transverse</concept>
	<concept>transversally</concept>
	<concept>transversely</concept>
 </defines>
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 <content>Transversality is a fundamental concept in differential topology. We say that two smooth submanifolds $A,B$ of a smooth manifold $M$ intersect \emph{transversely}, if at any point $x\in A\cap B$, we have
\[ T_x A + T_x B = T_x X, \]
where $T_x$ denotes the tangent space at $x$, and we naturally identify $T_x A$ and $T_x B$ with subspaces of $T_x X$. 

In this case, $A$ and $B$ intersect properly in the sense that $A\cap B$ is a submanifold of $M$, and
\[ \mathrm{codim}(A\cap B) = \mathrm{codim}(A) + \mathrm{codim}(B). \]

A useful generalization is obtained if we replace the inclusion $A\hookrightarrow M$ with a smooth map $f:A\to M$. In this case we say that $f$ is transverse to $B\subset M$, if for each point $a\in f^{-1}(B)$, we have
\[ df_a(T_a A) + T_{f(a)}B = T_{f(a)}M. \]
In this case it turns out, that $f^{-1}(B)$ is a submanifold of $A$, and
\[ \mathrm{codim}(f^{-1}(B)) = \mathrm{codim}(B).\]

Note that if $B$ is a single point $b$, then the condition of $f$ being transverse to $B$ is precisely that $b$ is a regular value for $f$. The result is that $f^{-1}(b)$ is a submanifold of $A$. A further generalization can be obtained by replacing the inclusion of $B$ by a smooth function as well. We leave the details to the reader. 

The importance of transversality is that it's a stable and generic condition. This means, in broad terms that if $f:A\to M$ is transverse to $B\subset M$, then small perturbations of $f$ are also transverse to $B$. Also, given any smooth map $A\to M$, it can be perturbed slightly to obtain a smooth map which is transverse to a given submanifold $B\subset M$.</content>
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