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<record version="2" id="4119">
 <title>generalized Kronecker delta symbol</title>
 <name>GeneralizedKroneckerDeltaSymbol</name>
 <created>2003-03-22 15:57:54</created>
 <modified>2003-03-23 02:48:08</modified>
 <type>Definition</type>
 <creator id="1858" name="matte"/>
 <author id="1858" name="matte"/>
 <classification>
	<category scheme="msc" code="15A99"/>
 </classification>
 <related>
	<object name="LeviCivitaPermutationSymbol3"/>
 </related>
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 <content>Let $l$ and $n$ be natural numbers such that $1\le l \le n$. 
Further,  let $i_k$  and $j_k$ be natural numbers in $\{1,\cdots, n\}$ 
for all $k$ in $\{1,\cdots, l\}$. 
Then the
\emph{generalized Kronecker delta symbol}, denoted by 
$\delta_{j_1\cdots j_l}\!\!\!\!\!\!\!\!\!\!^{i_1\cdots i_l}$, 
is zero if $i_r=i_s$ 
or $j_r=j_s$ for some $r\neq s$, or if
$\{i_1,\cdots, i_l\} \neq \{j_1,\cdots, j_l\}$ as sets.
If none of the above conditions are met, then 
$\delta_{j_1\cdots j_l}\!\!\!\!\!\!\!\!\!\!^{i_1\cdots i_l}$ 
is defined as the sign of the permutation that maps
$i_1\cdots i_l$ to $j_1\cdots j_l$.

From the definition, it follows that when $l=1$, 
the generalized Kronecker delta symbol reduces to 
the traditional delta symbol $\delta^i_j$. 
Also, for $l=n$, we obtain 
\begin{eqnarray*}
\delta_{j_1\cdots j_n}\!\!\!\!\!\!\!\!\!\!\!\!^{i_1\cdots \,i_n}&amp;=&amp;\varepsilon^{i_1\cdots i_n}\varepsilon_{j_1\cdots j_n},\\
\delta_{j_1\cdots j_n}\!\!\!\!\!\!\!\!\!\!\!\!^{1\cdots \,n}&amp;=&amp;\varepsilon_{j_1\cdots j_n},
\end{eqnarray*}
where $\varepsilon_{j_1\cdots j_n}$ is the Levi-Civita permutation symbol.

For any $l$ we can write the generalized delta function 
as a determinant of traditional delta symbols. Indeed,
if $S(l)$ is the permutation group of $l$ elements, then 
\begin{eqnarray*}
\delta_{j_1\cdots j_l}\!\!\!\!\!\!\!\!\!\!\!^{i_1\cdots i_l} &amp;=&amp; \sum_{\tau\in S(l)} \mbox{sign} \, \tau\, \delta^{i_{\tau(1)}}_{j_1}\cdots \delta^{i_{\tau(l)}}_{j_l} \\
&amp;=&amp; \det \left(  \begin {array}{lll} \delta^{i_1}_{j_1} &amp; \cdots &amp; \delta^{i_l}_{j_1} \\
   \vdots &amp; \ddots &amp; \vdots \\
   \delta^{i_1}_{j_l} &amp;  \cdots &amp; \delta^{i_l}_{j_l} 
    \end{array} \right).
\end{eqnarray*}
The first equality follows since the sum one the first line has only one non-zero term; the term for
which $i_{\tau(k)} = j_k$. The second equality follows from the 
definition of the determinant.</content>
</record>
