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<record version="7" id="434">
 <title>permutation</title>
 <name>Permutation</name>
 <created>2001-10-20 23:29:24</created>
 <modified>2007-10-22 10:22:38</modified>
 <type>Definition</type>
 <creator id="2414" name="alozano"/>
 <author id="2414" name="alozano"/>
 <author id="6075" name="rspuzio"/>
 <author id="3" name="drini"/>
 <classification>
	<category scheme="msc" code="20B99"/>
	<category scheme="msc" code="03-00"/>
	<category scheme="msc" code="05A05"/>
 </classification>
 <related>
	<object name="Bijection"/>
	<object name="Function"/>
	<object name="Cycle2"/>
	<object name="CycleNotation"/>
	<object name="OneLineNotationForPermutations"/>
 </related>
 <keywords>
	<term>Combinatorics</term>
 </keywords>
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 <content>A \emph{permutation} of a finite set $\{a_1,a_2,\ldots,a_n\}$ is an arrangement of its elements.
For example, if $S=\{A,B,C\}$ then $A B C$, $C A B$ , $C B A$ are three different permutations of $S$.

The number of permutations of a set with $n$ elements is $n!$.

A permutation can also be seen as a bijective function of a set into itself.
For example, the permutation $A B C \mapsto C A B$ could be seen a function $f:\{A,B,C\} \to \{A,B,C\}$ that assigns:
$$f(A)=C,\qquad f(B)=A,\qquad f(C)=B.$$

In fact, every bijection of a set into itself gives a permutation, and any permutation gives rise to  a bijective function.

Therefore, we can say that there are $n!$ bijective functions from a set with $n$ elements into itself.


Using the function approach, it can be proved that any permutation can be expressed as a composition of disjoint cycles and also as composition of (not necessarily disjoint) transpositions.

Moreover, if $\sigma=\tau_1\tau_2\cdots\tau_m=\rho_1\rho_2\cdots\rho_n$ are two factorization of a permutation $\sigma$ into transpositions, then $m$ and $n$ must be both even or both odd. So we can label permutations as \emph{even} or \emph{odd} depending on the number of transpositions for any decomposition.

Permutations (as functions) form in general a non-abelian group with function composition as binary operation called \emph{symmetric group of order $n$}. The subset of even permutations becomes a subgroup called the alternating group of order $n$.</content>
</record>
