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<record version="4" id="4426">
 <title>bounded function</title>
 <name>BoundedFunction</name>
 <created>2003-07-06 11:48:55</created>
 <modified>2004-12-11 11:07:47</modified>
 <type>Definition</type>
 <creator id="127" name="Koro"/>
 <author id="127" name="Koro"/>
 <author id="1858" name="matte"/>
 <classification>
	<category scheme="msc" code="46-00"/>
 </classification>
 <defines>
	<concept>supremum norm</concept>
	<concept>sup norm</concept>
	<concept>sup-norm</concept>
	<concept>uniform norm</concept>
	<concept>bounded function</concept>
	<concept>unbounded function</concept>
 </defines>
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 <content>{\bf Definition} Suppose  $X$ is a nonempty set. Then a function
$f:X\to \sC$ is a \emph{\PMlinkescapetext{bounded function}} 
if there exist a $C&lt;\infty$ such that 
$|f(x)|&lt;C$ for all $x\in X$. The 
set of all bounded functions on $X$ is usually 
denoted by $B(X)$ (\cite{aliprantis}, pp. 61).

Under standard point-wise addition and point-wise multiplication by
a scalar, $B(X)$ is a complex vector space. 

If $f\in B(X)$, then the \emph{sup-norm}, or \emph{uniform norm}, of $f$ 
is defined as 
$$ ||f||_\infty = \sup_{x\in X} |f(x)|. $$
It is straightforward to check that $||\cdot||_\infty$ makes $B(X)$ into
a normed vector space, i.e., to check that $||\cdot||_\infty$ satisfies the 
assumptions for a norm. 

\subsubsection{Example}
Suppose $X$ is a compact topological space. Further, let $C(X)$ be the
set of continuous complex-valued functions on $X$ (with the same vector
space structure as $B(X)$). Then $C(X)$ is a vector subspace of $B(X)$. 

\begin{thebibliography}{9}
\bibitem{aliprantis}
 C.D. Aliprantis, O. Burkinshaw, \emph{Principles of Real Analysis}, 
 2nd ed., Academic Press, 1990.
\end{thebibliography}</content>
</record>
