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<record version="5" id="4433">
 <title>every locally integrable function is a distribution</title>
 <name>EveryLocallyIntegrableFunctionIsADistribution</name>
 <created>2003-07-09 05:13:30</created>
 <modified>2006-01-30 06:58:09</modified>
 <type>Theorem</type>
<parent id="4427">distribution</parent>
 <creator id="1858" name="matte"/>
 <author id="2760" name="yark"/>
 <author id="1858" name="matte"/>
 <classification>
	<category scheme="msc" code="46F05"/>
	<category scheme="msc" code="46-00"/>
 </classification>
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 <content>\newcommand{\cD}[0]{\mathcal{D}}

Suppose $U$ is an open set in $\sR^n$ and $f$ is a locally
integrable function on $U$, i.e., $f\in L^1_{\scriptsize{\mbox{loc}}}(U)$.
Then the mapping
\begin{eqnarray*}
T_f: \cD(U) &amp;\to&amp; \sC \\
     u      &amp;\mapsto&amp; \int_U f(x) u(x) dx
\end{eqnarray*}
is a zeroth order distribution. (See parent entry for notation $\cD(U)$.)

\PMlinkname{(proof)}{T_fIsADistributionOfZerothOrder}

If $f$ and $g$ are both locally integrable functions on an open set $U$,
and $T_f=T_g$, then it follows (see 
\PMlinkname{this page}{TheoremForLocallyIntegrableFunctions}),
that $f=g$ almost everywhere. Thus, the mapping $f\mapsto T_f$
is a linear injection when $L^1_{\scriptsize{\mbox{loc}}}$ is equipped with
the usual equivalence relation for an $L^p$-space. For this reason,
one usually writes $f$ for the distribution $T_f$.</content>
</record>
