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<record version="5" id="4527">
 <title>self-adjoint operator</title>
 <name>SelfAdjointOperator</name>
 <created>2003-07-28 12:59:30</created>
 <modified>2006-06-15 19:31:03</modified>
 <type>Definition</type>
 <creator id="127" name="Koro"/>
 <author id="127" name="Koro"/>
 <classification>
	<category scheme="msc" code="47B15"/>
	<category scheme="msc" code="47B25"/>
 </classification>
 <defines>
	<concept>Hermitian operator</concept>
	<concept>symmetric operator</concept>
	<concept>essentially self-adjoint</concept>
	<concept>self-adjoint</concept>
 </defines>
 <related>
	<object name="HermitianMatrix"/>
 </related>
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 <content>\PMlinkescapeword{symmetric} \PMlinkescapeword{Hermitian}
A densely defined linear operator $A\colon\mathscr{D}(A)\subset \mathscr{H}\to\mathscr{H}$ on a Hilbert space $\mathscr{H}$ is a \emph{Hermitian} or \emph{symmetric} operator if $(Ax,y) = (x,Ay)$ for all $x,y\in \mathscr{D}(A)$. This means that the adjoint $A^*$ of $A$ is defined at least on $\mathscr{D}(A)$ and that its restriction to that set coincides with $A$. This fact is often denoted by $A\subset A^*$.

The operator $A$ is \emph{self-adjoint} if it coincides with its adjoint, i.e. if $A=A^*$.
If $A$ is closable and its closure coincides with its adjoint (i.e. $\overline{A}=A^*$), then $A$ is said to be \emph{essentially self-adjoint}.</content>
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