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 <title>transcendence degree</title>
 <name>TransendenceDegree</name>
 <created>2003-09-25 17:46:21</created>
 <modified>2007-05-09 22:05:10</modified>
 <type>Definition</type>
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	<category scheme="msc" code="12F20"/>
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 <defines>
	<concept>transcendence degree of a set</concept>
	<concept>transcendence degree of a field extension</concept>
 </defines>
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 <content>The \emph{transcendence degree} of a set $S$ over a field $K$, denoted $T_S$, is the size of the maximal subset $S'$ of $S$ such that all the elements of $S'$ are algebraically independent.

The \emph{transcendence degree} of a field extension $L$ over $K$ is the transcendence degree of the minimal subset of $L$ needed to generate $L$ over $K$.

Heuristically speaking, the transcendence degree of a finite set $S$ is obtained by taking the number of elements in the set, subtracting the number of algebraic elements in that set, and then subtracting the number of algebraic relations between distinct pairs of elements in $S$.

\begin{Exam}[Computing the Transcendence Degree]
The set $S=\{\sqrt{7}, \pi, \pi^2, e\}$ has transcendence $T_S\leq2$ over $\mathbb{Q}$ since there are
four elements, $\sqrt{7}$ is algebraic, and the polynomial
$f(x,y)=x^2-y$ gives an algebraic dependence between $\pi$ and $\pi^2$
(i.e.  $(\pi,\pi^2)$ is a root of $f$), giving $T_S\leq4-1-1=2$.  If
we assume the conjecture that $e$ and $\pi$ are algebraically
independent, then no more dependencies can exist, and we can conclude
that, in fact, $T_S=2$.
\end{Exam}</content>
</record>
