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<record version="10" id="4844">
 <title>semicontinuous</title>
 <name>LowerSemicontinuous</name>
 <created>2003-10-15 01:05:31</created>
 <modified>2007-05-09 19:01:26</modified>
 <type>Definition</type>
 <creator id="988" name="bwebste"/>
 <author id="17056" name="adrianita"/>
 <author id="2760" name="yark"/>
 <author id="11940" name="via_strass"/>
 <author id="1858" name="matte"/>
 <author id="3284" name="apmxi"/>
 <classification>
	<category scheme="msc" code="26A15"/>
 </classification>
 <defines>
	<concept>lower semicontinuous</concept>
	<concept>upper semicontinuous</concept>
	<concept>lower semi-continuous</concept>
	<concept>upper semi-continuous</concept>
 </defines>
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 <content>Suppose $X$ is a topological space, and $f$ is a function
from $X$ into the extended real numbers $\mathbb{R}^*$; $f:X\to \mathbb{R}^*$.
Then:
\begin{enumerate}
\item
If
$f^{-1}((\alpha,\infty])=\{x\in X \mid f(x) &gt;\alpha\}$ 
is an open set in $X$ for all $\alpha\in \mathbb{R}$,
then $f$ is said to be {\bf lower semicontinuous}.
\item
If
$f^{-1}([-\infty,\alpha))=\{x\in X \mid f(x) &lt;\alpha\}$ 
is an open set in $X$ for all $\alpha\in \mathbb{R}$,
then $f$ is said to be {\bf upper semicontinuous}.
\end{enumerate}

In other words, $f$ is lower semicontinuous, if $f$ is continuous with 
respect to the topology for $\mathbb{R}^*$ containing $\emptyset$ and 
open sets
$$
   U(\alpha) = (\alpha,\infty], \quad \quad \alpha\in \mathbb{R}\cup \{-\infty\}.
$$
It is not difficult to see that this is a topology. For example, 
for a union of sets $U(\alpha_i)$ we have $\cup_i U(\alpha_i)=U(\inf \alpha_i)$. 
Obviously, this topology is much coarser than
the usual topology for the extended numbers. 
However,
the sets $U(\alpha)$ can be seen as neighborhoods of infinity, so
in some sense, semicontinuous functions are "continuous at infinity"
(see example 3 below). 

\subsubsection{Examples}
\begin{enumerate}
\item A function $f\colon X\to \mathbb{R}^*$ is continuous if and only if 
it is lower and upper semicontinuous. 
\item Let $f$ be the characteristic function of a set $\Omega\subseteq X$. 
Then $f$ is lower (upper)
  semicontinuous if and only if $\Omega$ is open (closed).
This also holds for the function that
  equals $\infty$ in the set and $0\,$ outside. 
  
It follows that the characteristic function of $\Q$ is not
semicontinuous.

\item On $\mathbb{R}$, the function $f(x)=1/x$ for $x\neq 0$ and $f(0)=0$, is not
semicontinuous. This example illustrate how semicontinuous "at infinity".
\end{enumerate}
  
\subsubsection{Properties}

Let $f\colon X\to \mathbb{R}^*$ be a function.
\begin{enumerate}
\item Restricting $f$ to a subspace preserves semicontinuity.
\item Suppose $f$ is upper (lower) semicontinuous, $A$ is a topological space, and 
$\Psi\colon A\to X$ is a homeomorphism. Then $f\circ\Psi$ is upper (lower) semicontinuous. 
\item Suppose $f$ is upper (lower) semicontinuous, and 
$S\colon \mathbb{R}^*\to \mathbb{R}^*$ is a sense preserving homeomorphism. 
Then $S\circ f$ is upper (lower) semicontinuous. 
\item $f$ is lower semicontinuous if and only if 
$-f$ is upper semicontinuous.
\end{enumerate}

\begin{thebibliography}{9}
 \bibitem{rudin_real}
 W. Rudin, \emph{Real and complex analysis}, 3rd ed., McGraw-Hill Inc., 1987.
\bibitem{cohn}
 D.L. Cohn, \emph{Measure Theory}, Birkh\"auser, 1980.
 \end{thebibliography}</content>
</record>
