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<record version="2" id="5520">
 <title>complete measure</title>
 <name>CompleteMeasure</name>
 <created>2004-01-18 16:24:02</created>
 <modified>2004-01-18 16:57:03</modified>
 <type>Definition</type>
 <creator id="127" name="Koro"/>
 <author id="127" name="Koro"/>
 <classification>
	<category scheme="msc" code="28A12"/>
 </classification>
 <defines>
	<concept>completion</concept>
	<concept>complete</concept>
 </defines>
 <related>
	<object name="UniversallyMeasurable"/>
 </related>
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 <content>A measure space $(X,\mathscr{S},\mu)$ is said to be \emph{complete} if every subset of a set of measure $0$ is measurable (and consequently, has measure $0$); i.e. if for all $E\in\mathscr{S}$ such that $\mu(E)=0$ and for all $S\subset E$ we have $\mu(S)=0$. 

If a measure space is not complete, there exists a \PMlinkname{completion}{CompletionOfAMeasureSpace} of it, which is a complete measure space $(X,\overline{\mathscr{S}},\overline{\mu})$ such that $\mathscr{S}\subset\overline{\mathscr{S}}$ and $\overline {\mu}_{|\mathscr{S}} = \mu$, where $\overline{\mathscr{S}}$ is the smallest $\sigma$-algebra containing both $\mathscr{S}$ and all subsets of elements of zero measure of $\mathscr{S}$.</content>
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