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<record version="6" id="576">
 <title>joint continuous density function</title>
 <name>JointContinousDensityFunction</name>
 <created>2001-10-26 19:44:36</created>
 <modified>2006-10-25 00:15:55</modified>
 <type>Definition</type>
 <creator id="2727" name="mathcam"/>
 <author id="2727" name="mathcam"/>
 <author id="23" name="Riemann"/>
 <classification>
	<category scheme="msc" code="60A10"/>
 </classification>
 <synonyms>
	<synonym concept="joint continuous density function" alias="joint mass function"/>
	<synonym concept="joint continuous density function" alias="joint density function"/>
	<synonym concept="joint continuous density function" alias="joint distribution"/>
 </synonyms>
 <keywords>
	<term>statistics</term>
 </keywords>
 <preamble>\usepackage{amssymb}
\usepackage{amsmath}
\usepackage{amsfonts}
\usepackage{graphicx}
\usepackage{xypic}</preamble>
 <content>Let $X_1, X_2, ..., X_n$ be $n$ random variables all defined on the same probability space. The \textbf{joint continuous density function} of $X_1, X_2, ..., X_n$, denoted by $f_{X_1, X_2, ..., X_n}(x_1,x_2,...,x_n)$, is the function
$f_{X_1, X_2, ..., X_n}: \mathbb{R}^n \to \mathbb{R}$ such that for any domain $D\subset \mathbb{R}^n$, we have
\begin{align*}
\int_D  {  f_{X_1,X_2,..., X_n}(u_1,u_2,...,u_n) du_1 du_2 ... du_n  } = \text{Prob}({X_1,X_2,...,X_n}\in D)
\end{align*}
\par
As in the case where $n=1$, this function satisfies:\\
\par
\begin{enumerate}
\item $f_{X_1, X_2, ..., X_n}(x_1,...,x_n) \geq  0$    $\forall (x_1,...,x_n)$
\item $\int_{x_1, ... ,x_n}^{} {  f_{X_1, X_2, ..., X_n}(u_1,u_2,...,u_n) du_1 du_2 ... du_n }= 1$
\end{enumerate}
\par
As in the single variable case, $f_{X_1, X_2, ..., X_n}$ does not represent the probability that each of the random variables takes on each of the values.</content>
</record>
