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<record version="6" id="5852">
 <title>category isomorphism</title>
 <name>CategoryIsomorphism</name>
 <created>2004-05-11 13:15:39</created>
 <modified>2007-06-16 14:45:01</modified>
 <type>Definition</type>
 <creator id="3771" name="CWoo"/>
 <author id="409" name="mps"/>
 <author id="3771" name="CWoo"/>
 <classification>
	<category scheme="msc" code="18A05"/>
 </classification>
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 <content>Let $\mathcal{C}$ and $\mathcal{D}$ be categories.  An
\emph{isomorphism} $T:\mathcal{C}\to\mathcal{D}$ is a (covariant)
functor which has a \emph{two-sided inverse}.  In other words, there
is a (covariant) functor $S:\mathcal{D}\to\mathcal{C}$ such that
$T\circ S=I_{\mathcal{D}}$ and $S\circ T=I_{\mathcal{C}}$, where
$I_{\mathcal{D}}$ and $I_{\mathcal{C}}$ are the identity functors of
$\mathcal{D}$ and $\mathcal{C}$ respectively.  Two categories
$\mathcal{C}$ and $\mathcal{D}$ are \emph{isomorphic} if there exists
a functor $T:\mathcal{C}\to\mathcal{D}$ that is an isomorphism.

\textbf{Remarks}
\begin{enumerate}
\item
An isomorphism (functor) from $\mathcal{C}$ to $\mathcal{D}$ is just
an \PMlinkname{isomorphism}{Isomorphism2} (in the sense of morphism)
in the functor category $\mathcal{D}^{\mathcal{C}}$.

\item
Two isomorphic categories are
\PMlinkname{equivalent}{EquivalenceOfCategories}.  The converse is not
true.  For example, the category of all finite sets is
\PMlinkescapetext{equivalent} to its subcategory of all finite
ordinals.  But clearly these two categories are not isomorphic.
Isomorphism has a ``size'' restriction, whereas natural equivalence
does not.  
\end{enumerate}

\PMlinkescapeword{isomorphism}
\PMlinkescapeword{isomorphic}
\PMlinkescapeword{restriction}

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