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<record version="5" id="5929">
 <title>telescoping sum</title>
 <name>TelescopingSum</name>
 <created>2004-06-17 10:56:37</created>
 <modified>2008-05-03 14:35:02</modified>
 <type>Definition</type>
 <creator id="11260" name="cvalente"/>
 <author id="11260" name="cvalente"/>
 <author id="225" name="saforres"/>
 <classification>
	<category scheme="msc" code="40A05"/>
 </classification>
 <defines>
	<concept>telescope</concept>
 </defines>
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 <content>A {\em telescoping sum} is a sum in which cancellation occurs between subsequent terms, allowing the sum to be expressed using only the initial and final terms.

Formally a telescoping sum is or can be rewritten in the form

$$ S= \sum_{n=\alpha}^{\beta}\left(a_n - a_{n+1}\right) = a_\alpha - a_{\beta+1}$$

where $a_n$ is a sequence.

{\bf Example:}\\

Define $S(N) = \sum_{n=1}^{N} \frac{1}{n(n+1)}$.  Note that by partial fractions of expressions:
\[ \frac{1}{n(n+1)}= \frac{1}{n} - \frac{1}{n+1} \] and thus $a_n = \frac{1}{n}$ in this example.

\[ S(N) = \sum_{n=1}^{N} \left( \frac{1}{n} - \frac{1}{n+1} \right) \]
\[  = \left( 1 - \frac{1}{2} \right)
      + \cdots + \left( \frac{1}{n} - \frac{1}{n+1} \right) +
      \left( \frac{1}{n+1} - \frac{1}{n+2} \right)
      + \cdots + \left( \frac{1}{N} - \frac{1}{N+1} \right) \]
\[  = 1 + \left( - \frac{1}{2} + \frac{1}{2} \right)
      + \cdots + \left( -\frac{1}{n+1} +\frac{1}{n+1} \right)
      + \cdots - \frac{1}{N+1} \]
\[  = 1 - \frac{1}{N+1} \]</content>
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