<?xml version="1.0" encoding="UTF-8"?>

<record version="1" id="5984">
 <title>set of sampling</title>
 <name>SetOfSampling</name>
 <created>2004-07-06 20:06:13</created>
 <modified>2004-07-06 20:06:13</modified>
 <type>Definition</type>
 <creator id="1337" name="swiftset"/>
 <author id="1337" name="swiftset"/>
 <classification>
	<category scheme="msc" code="46C99"/>
 </classification>
 <defines>
	<concept>set of sampling</concept>
	<concept>sampling operator</concept>
 </defines>
 <synonyms>
	<synonym concept="set of sampling" alias="sampling set"/>
 </synonyms>
 <related>
	<object name="Frame2"/>
 </related>
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 <content>\paragraph{Definition}
Let $F$ be a Hilbert space of functions defined on a domain $D$. Let $T = \{t_i\}_{i\in I}$ be a finite or infinite sequence of points in $D$. $T$ is said to be a \emph{set of sampling} for $F$ if the sampling operator $S: F \rightarrow l^2_{|T|}$ defined by 
$$ 
S: f \mapsto 
\begin{pmatrix}
f(t_1) \\
f(t_2) \\
\vdots 
\end{pmatrix}
$$
is bounded (i.e. continuous) and bounded below; i.e. if 
$$\exists A,B&gt;0 \hbox{ such that } \forall f \in F, A\|f\|^2 \leq \sum_{i=1}^{|T|} |f(t_i)|^2 \leq B \|f\|^2.$$

\paragraph{Relation to Frames}
Using the Riesz Representation Theorem, it is easy to show that every set of sampling determines a unique frame in such a way that the analysis operator of that frame is the sampling operator associated with the set of sampling. In fact, let $t=\{t_i\}$ be a set of sampling with sampling operator $S_t$. Use the Riesz representation theorem to rewrite $S_t$ in terms of vectors $\{g_i\}$ in $F$:
$$ 
S: f \mapsto 
\begin{pmatrix}
f(t_1) \\
f(t_2) \\
\vdots
\end{pmatrix}
=
\begin{pmatrix}
\langle f, g_1 \rangle \\
\langle f, g_2 \rangle \\
\vdots
\end{pmatrix}
$$
then note that 
$$ \forall f\in F, A\|f\|^2 \leq \sum_{i} \left| \langle f, g_i \rangle \right|^2 \leq B\|f\|^2, $$
so the $\{g_i\}$ form a frame with bounds $A, B$, and $S_t = \theta_g.$

\paragraph{Reconstruction}
Particularly nice sets of sampling are those that correspond to tight frames, because then $\theta_g^\ast\theta_g=\theta_g^\ast S_t=AI$, and it is possible to reconstruct the function $f$, given its values over the set of sampling:
$$ f = \frac{1}{A}\sum_i f(t_i) g_i.$$
Sets of sampling which correspond to tight frames are referred to as tight sets of sampling.</content>
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