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<record version="3" id="6278">
 <title>radius of convergence of a complex function</title>
 <name>RadiusOfConvergenceOfAComplexFunction</name>
 <created>2004-10-03 01:01:23</created>
 <modified>2004-10-05 02:04:30</modified>
 <type>Theorem</type>
 <creator id="6075" name="rspuzio"/>
 <author id="6075" name="rspuzio"/>
 <classification>
	<category scheme="msc" code="30B10"/>
 </classification>
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 <content>Let $f$ be an analytic function defined in a disk of radius $R$ about a point $z_0 \in \mathbb{C}$.  Then the radius of convergence of the Taylor series of $f$ about $z_0$ is at least $R$.

For example, the function $a(z) = 1 / (1 - z)^2$ is analytic inside the disk $|z| &lt; 1$.  Hence its the radius of covergence of its Taylor series about $0$ is at least $1$.  By direct examination of the Taylor series we can see that its radius of convergence is, in fact, equal to $1$.

Colloquially, this theorem is stated in the sometimes imprecise but memorable form ``The radius of convergence of the Taylor series is the distance to the nearest singularity.''</content>
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